[Python-checkins] cpython: cleanup datetime code
victor.stinner
python-checkins at python.org
Wed Sep 9 01:09:41 CEST 2015
https://hg.python.org/cpython/rev/46d812637efd
changeset: 97783:46d812637efd
user: Victor Stinner <victor.stinner at gmail.com>
date: Wed Sep 09 01:09:21 2015 +0200
summary:
cleanup datetime code
remove scories of round half up code and debug code.
files:
Lib/datetime.py | 7 -------
Lib/test/datetimetester.py | 2 +-
2 files changed, 1 insertions(+), 8 deletions(-)
diff --git a/Lib/datetime.py b/Lib/datetime.py
--- a/Lib/datetime.py
+++ b/Lib/datetime.py
@@ -316,13 +316,6 @@
return q
-def _round_half_up(x):
- """Round to nearest with ties going away from zero."""
- if x >= 0.0:
- return _math.floor(x + 0.5)
- else:
- return _math.ceil(x - 0.5)
-
class timedelta:
"""Represent the difference between two datetime objects.
diff --git a/Lib/test/datetimetester.py b/Lib/test/datetimetester.py
--- a/Lib/test/datetimetester.py
+++ b/Lib/test/datetimetester.py
@@ -679,7 +679,7 @@
us_per_day = us_per_hour * 24
eq(td(days=.4/us_per_day), td(0))
eq(td(hours=.2/us_per_hour), td(0))
- eq(td(days=.4/us_per_day, hours=.2/us_per_hour), td(microseconds=1), td)
+ eq(td(days=.4/us_per_day, hours=.2/us_per_hour), td(microseconds=1))
eq(td(days=-.4/us_per_day), td(0))
eq(td(hours=-.2/us_per_hour), td(0))
--
Repository URL: https://hg.python.org/cpython
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