[Python-checkins] cpython (2.7): #20135: move FAQ about mutable default arguments to the programming FAQs page.

[ezio.melotti]

http://hg.python.org/cpython/rev/3881c12fa3ae
changeset:   91557:3881c12fa3ae
branch:      2.7
parent:      91545:5563f895b215
user:        Ezio Melotti <ezio.melotti at gmail.com>
date:        Sun Jul 06 20:53:27 2014 +0300
summary:
  #20135: move FAQ about mutable default arguments to the programming FAQs page.

files:
  Doc/faq/design.rst      |  56 -----------------------------
  Doc/faq/programming.rst |  56 +++++++++++++++++++++++++++++
  2 files changed, 56 insertions(+), 56 deletions(-)


diff --git a/Doc/faq/design.rst b/Doc/faq/design.rst
--- a/Doc/faq/design.rst
+++ b/Doc/faq/design.rst
@@ -712,62 +712,6 @@
 sloppy and not write test cases at all.
 
 
-Why are default values shared between objects?
-----------------------------------------------
-
-This type of bug commonly bites neophyte programmers.  Consider this function::
-
-   def foo(mydict={}):  # Danger: shared reference to one dict for all calls
-       ... compute something ...
-       mydict[key] = value
-       return mydict
-
-The first time you call this function, ``mydict`` contains a single item.  The
-second time, ``mydict`` contains two items because when ``foo()`` begins
-executing, ``mydict`` starts out with an item already in it.
-
-It is often expected that a function call creates new objects for default
-values. This is not what happens. Default values are created exactly once, when
-the function is defined.  If that object is changed, like the dictionary in this
-example, subsequent calls to the function will refer to this changed object.
-
-By definition, immutable objects such as numbers, strings, tuples, and ``None``,
-are safe from change. Changes to mutable objects such as dictionaries, lists,
-and class instances can lead to confusion.
-
-Because of this feature, it is good programming practice to not use mutable
-objects as default values.  Instead, use ``None`` as the default value and
-inside the function, check if the parameter is ``None`` and create a new
-list/dictionary/whatever if it is.  For example, don't write::
-
-   def foo(mydict={}):
-       ...
-
-but::
-
-   def foo(mydict=None):
-       if mydict is None:
-           mydict = {}  # create a new dict for local namespace
-
-This feature can be useful.  When you have a function that's time-consuming to
-compute, a common technique is to cache the parameters and the resulting value
-of each call to the function, and return the cached value if the same value is
-requested again.  This is called "memoizing", and can be implemented like this::
-
-   # Callers will never provide a third parameter for this function.
-   def expensive(arg1, arg2, _cache={}):
-       if (arg1, arg2) in _cache:
-           return _cache[(arg1, arg2)]
-
-       # Calculate the value
-       result = ... expensive computation ...
-       _cache[(arg1, arg2)] = result           # Store result in the cache
-       return result
-
-You could use a global variable containing a dictionary instead of the default
-value; it's a matter of taste.
-
-
 Why is there no goto?
 ---------------------
 
diff --git a/Doc/faq/programming.rst b/Doc/faq/programming.rst
--- a/Doc/faq/programming.rst
+++ b/Doc/faq/programming.rst
@@ -499,6 +499,62 @@
 occur when the module is initialized.
 
 
+Why are default values shared between objects?
+----------------------------------------------
+
+This type of bug commonly bites neophyte programmers.  Consider this function::
+
+   def foo(mydict={}):  # Danger: shared reference to one dict for all calls
+       ... compute something ...
+       mydict[key] = value
+       return mydict
+
+The first time you call this function, ``mydict`` contains a single item.  The
+second time, ``mydict`` contains two items because when ``foo()`` begins
+executing, ``mydict`` starts out with an item already in it.
+
+It is often expected that a function call creates new objects for default
+values. This is not what happens. Default values are created exactly once, when
+the function is defined.  If that object is changed, like the dictionary in this
+example, subsequent calls to the function will refer to this changed object.
+
+By definition, immutable objects such as numbers, strings, tuples, and ``None``,
+are safe from change. Changes to mutable objects such as dictionaries, lists,
+and class instances can lead to confusion.
+
+Because of this feature, it is good programming practice to not use mutable
+objects as default values.  Instead, use ``None`` as the default value and
+inside the function, check if the parameter is ``None`` and create a new
+list/dictionary/whatever if it is.  For example, don't write::
+
+   def foo(mydict={}):
+       ...
+
+but::
+
+   def foo(mydict=None):
+       if mydict is None:
+           mydict = {}  # create a new dict for local namespace
+
+This feature can be useful.  When you have a function that's time-consuming to
+compute, a common technique is to cache the parameters and the resulting value
+of each call to the function, and return the cached value if the same value is
+requested again.  This is called "memoizing", and can be implemented like this::
+
+   # Callers will never provide a third parameter for this function.
+   def expensive(arg1, arg2, _cache={}):
+       if (arg1, arg2) in _cache:
+           return _cache[(arg1, arg2)]
+
+       # Calculate the value
+       result = ... expensive computation ...
+       _cache[(arg1, arg2)] = result  # Store result in the cache
+       return result
+
+You could use a global variable containing a dictionary instead of the default
+value; it's a matter of taste.
+
+
 How can I pass optional or keyword parameters from one function to another?
 ---------------------------------------------------------------------------
 

-- 
Repository URL: http://hg.python.org/cpython