[Python-checkins] cpython (3.2): Issue #14641: minor fixes to sockets Howto; patch by Dionysios Kalofonos
sandro.tosi
python-checkins at python.org
Mon Apr 23 19:47:24 CEST 2012
http://hg.python.org/cpython/rev/9bb9604519ce
changeset: 76501:9bb9604519ce
branch: 3.2
parent: 76497:2a35dfbe3d99
user: Sandro Tosi <sandro.tosi at gmail.com>
date: Mon Apr 23 19:45:07 2012 +0200
summary:
Issue #14641: minor fixes to sockets Howto; patch by Dionysios Kalofonos
files:
Doc/howto/sockets.rst | 4 ++--
1 files changed, 2 insertions(+), 2 deletions(-)
diff --git a/Doc/howto/sockets.rst b/Doc/howto/sockets.rst
--- a/Doc/howto/sockets.rst
+++ b/Doc/howto/sockets.rst
@@ -153,7 +153,7 @@
there, you may wait forever for the reply, because the request may still be in
your output buffer.
-Now we come the major stumbling block of sockets - ``send`` and ``recv`` operate
+Now we come to the major stumbling block of sockets - ``send`` and ``recv`` operate
on the network buffers. They do not necessarily handle all the bytes you hand
them (or expect from them), because their major focus is handling the network
buffers. In general, they return when the associated network buffers have been
@@ -164,7 +164,7 @@
When a ``recv`` returns 0 bytes, it means the other side has closed (or is in
the process of closing) the connection. You will not receive any more data on
this connection. Ever. You may be able to send data successfully; I'll talk
-about that some on the next page.
+more about this later.
A protocol like HTTP uses a socket for only one transfer. The client sends a
request, then reads a reply. That's it. The socket is discarded. This means that
--
Repository URL: http://hg.python.org/cpython
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