[issue42165] closed (reopen with other issue)

[Eric V. Smith]

Eric V. Smith <eric at trueblade.com> added the comment:

To answer the question:

> "can anyone explain why "pickle.loads(np.float64(0.34104))" prints "True"

You can use pickletools.dis:

>>> bytes(np.float64(0.34104))
b'\x88.\xa8o\x99\xd3\xd5?'

>>> pickletools.dis(bytes(np.float64(0.34104)))
    0: \x88 NEWTRUE
    1: .    STOP

Note that pickle ignores anything after the end of the pickle (the STOP opcode), so only the first 2 bytes are being used.

As Serhiy said, it's just chance that the bytes returned by numpy happen to be a valid pickle for some values. You should not be trying to .loads() something that isn't a valid pickle stream. It's not clear why you think a byte string returned by np.float64 would be a valid pickle.

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nosy: +eric.smith
stage: resolved -> 
status: closed -> open

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<https://bugs.python.org/issue42165>
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