[issue42026] index function return first index for same element if repetitive in a list

[Raymond Hettinger]

Raymond Hettinger <raymond.hettinger at gmail.com> added the comment:

The index() method is working as expected.  This isn't a bug.

The easiest way to accomplish your goal is to use enumerate() with a list comprehension:

    >>> po = [11,22,33,44,11,55,66,11,88]
    >>> [i for i, value in enumerate(po) if value == 11]
    [0, 4, 7]

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nosy: +rhettinger

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue42026>
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