[issue40806] itertools.product not lazy

[Rémi Lapeyre]

Rémi Lapeyre <remi.lapeyre at henki.fr> added the comment:

Hi Ramil, itertools.product() expect its argument to be finite iterables, it needs to keep all their elements in memory anyway at it "cycles around" to produce all possible pairs.

Basically, product(x(1), x(2)) is equivalent to product(tuple(x(1)), tuple(x(2))).


I see that the documentation does not mention that the arguments must be finite, could you open a PR to improve it?

----------
nosy: +remi.lapeyre

_______________________________________
Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue40806>
_______________________________________