[issue40196] symtable.Symbol.is_local() can be True for global symbols

[Pablo Galindo Salgado]

Pablo Galindo Salgado <pablogsal at gmail.com> added the comment:

>>> code2 = """\
... def foo():
...    x = 42
...    def bar():
...       return -1
... """
>>> top.get_children()[0]
<Function SymbolTable for foo in ?>
>>> top = symtable.symtable(code2, "?", "exec")
>>> top.get_children()[0].lookup('x')._Symbol__scope == symtable.LOCAL
True

but if we return x from bar:

That fix is not correct. For instance consider:

>>> code = """\
... def foo():
...    x = 42
...    def bar():
...       return x
... """
>>> import symtable
>>> top = symtable.symtable(code, "?", "exec")
>>> top.get_children()[0].lookup('x')._Symbol__scope == symtable.LOCAL
False

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue40196>
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