[issue38769] generators are currently hashable

[Ammar Askar]

Ammar Askar <ammar at ammaraskar.com> added the comment:

An easier way to understand might be to just write out the generator expression "manually":

  def generator_expression():
    for k, v in sorted(self.__dict__.items()):
      yield k
  return hash(my_generator_expression())

Would you say that `generator_expression` here is mutable or immutable? The code that underpins how it generates values is clearly immutable just like functions but the values it closes over can be changed.

Another minimal example:

>>> def f():
...   yield from some_list
...
>>> some_list = [1,2,3]
>>> list(f())
[1, 2, 3]
>>> some_list = [1,2,3,4,5]
>>> list(f())
[1, 2, 3, 4, 5]

Would you say that `f` is immutable or mutable in this case?

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nosy: +ammar2

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue38769>
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