[issue36426] exec() issue when used inside function

[Nick Coghlan]

Nick Coghlan <ncoghlan at gmail.com> added the comment:

This is not a bug - to enable function level optimisations, the compiler must be able to see all local variable names at compile time.

In Python 2.x the exec statement implementation included special code to allow even function local variables to be rebound, but that special-casing was removed as part of the Python 3 change to convert exec from a statement to a builtin function (as per https://www.python.org/dev/peps/pep-3100/#core-language )

This means that to use exec() and reliably see the changes it makes to a namespace, you have to supply a reliably read/write dictionary of your own. 

Object instance dictionaries work well for this purpose, as you can then access the results as attributes on the instance:

```
>>> class Namespace:
...     pass
... 
>>> def f():
...     ns = Namespace()
...     exec("x = 1; y = 2", vars(ns))
...     print(ns.x)
...     print(ns.y)
... 
>>> f()
1
2
```

----------
resolution:  -> not a bug
stage:  -> resolved
status: open -> closed

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue36426>
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