[issue34291] UnboundLocalError raised on call to global

[Tim Peters]

Tim Peters <tim at python.org> added the comment:

Yes, the assignment does "hide the global definition of g".  But this determination is made at compile time, not at run time:  an assignment to `g` _anywhere_ inside `f()` makes _every_ appearance of `g` within `f()` local to `f`.

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nosy: +tim.peters

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue34291>
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