[issue10544] yield expression inside generator expression does nothing

[Ivan Levkivskyi]

Ivan Levkivskyi <levkivskyi at gmail.com> added the comment:

> Remind me what happens when you use `await` in a generator expression that survives the async function's scope?

Awaiting on f([1, 2]) will result in an async generator (even though yield never appears here). Yury explained why this happens in https://bugs.python.org/issue32113

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