[issue31969] re.groups() is not checking the arguments

[Narendra]

Narendra <cnrprfnl at gmail.com> added the comment:

Hi Storchaka,

As per re.groups(), its should work as below:

groups([default])
Return a tuple containing all the subgroups of the match, from 1 up to however many groups are in the pattern. The default argument is used for groups that did not participate in the match; it defaults to None. (Incompatibility note: in the original Python 1.5 release, if the tuple was one element long, a string would be returned instead. In later versions (from 1.5.1 on), a singleton tuple is returned in such cases.)

For example:

>>> m = re.match(r"(\d+)\.(\d+)", "24.1632")
>>> m.groups()
('24', '1632')
If we make the decimal place and everything after it optional, not all groups might participate in the match. These groups will default to None unless the default argument is given:

>>> m = re.match(r"(\d+)\.?(\d+)?", "24")
>>> m.groups()      # Second group defaults to None.
('24', None)
>>> m.groups('0')   # Now, the second group defaults to '0'.
('24', '0')

I tested some scenario as below:
Scenario: Suppose i have a match like 
m = re.match(r"(\d+)\.(\d+)", "24.1632")
Here if i pass m.groups(10000), then it should check if there is optional match (optional match, pattern which is specified using ?), it should print 10000 in that match and if not, it should throw error that there is no any optional match (didn't have any pattern with ?).

Expected Output:
>>> m.groups(10000)
There is no any optional argument to use 10000

Received Output:
>>> m.groups(10000)
'24', '1632')

Please review the above and provide your comments?

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resolution: not a bug -> 
status: closed -> open

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue31969>
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