[issue22807] uuid.uuid1() should use uuid_generate_time_safe() if available

[STINNER Victor]

STINNER Victor added the comment:

I don't understand well this change.

What am I supposed to do with an UUID with safe=False? Should I loop on the function until I get safe==True?


"safe for multiprocessing applications"

Does it mean unique on the whole system?

I looked at uuid_generate_time_safe(3) manual page which mention "synchronization mechanisms (see above)" but they are not documented.
http://manpages.ubuntu.com/manpages/zesty/en/man3/uuid_generate.3.html


> I'm classifying this as a security issue, (...)

This issue was only fixed in Python 3.7. Does it mean that it's no more considered as as security vulnerability?

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resolution: fixed -> 
status: closed -> open

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue22807>
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