[issue29015] re slashes

[Serhiy Storchaka]

Serhiy Storchaka added the comment:

There is a problem with your replacement template. Python string literal '\\' is Python string containing a single backslash character. But backslash has special meaning in a replacement template, it starts escapes and backreferences. For using a literal backslash, it should be escaped: r'\\' or '\\\\'.

>>> re.sub(pat, r'\\', path)
'd:\\temp\\'

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nosy: +serhiy.storchaka
resolution:  -> not a bug
stage:  -> resolved
status: open -> closed

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<http://bugs.python.org/issue29015>
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