[issue22515] Implement partial order on Counter

[Ram Rachum]

Ram Rachum added the comment:

Ethan, I don't understand what the problem is. I also don't understand your side note question "how does partial-ordering work for sets?" I'm not sure what you're asking. 

>> That is, one counter will be considered smaller-or-equal to another if for any
>> item in the first counter, the second counter has an equal or bigger amount of
>> that item.

> According to your definition, my example should have returned True, which is clearly nonsensical.

In your example the first counter had `b` twice, while the second counter had it only once. So the result is `False`. This comes pretty directly from my definition, I'm not sure where the confusion is. 

Regarding your new example: Since `Counter` works like a `defaultdict`, the second counter has a zero quantity of `b`. So the answer is again `False`.

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue22515>
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