[issue22123] Make object() behave exactly like types.SimpleNamespace() if given kwargs

[Serhiy Storchaka]

Serhiy Storchaka added the comment:

This will be fragile because the behavior will be depend from the number of keyword argument. Hypothetic example:

>>> kwargs = {'a': 1}
>>> obj = object(**kwargs)
>>> obj.b = 2  # success
>>> kwargs = {}  # empty
>>> obj = object(**kwargs)
>>> obj.b = 2
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'object' object has no attribute 'b'

For now you need only one or two line of code to declare new class.

>>> class Object: pass
... 
>>> obj = Object()
>>> obj.a = 1
>>> obj.b = 2

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nosy: +serhiy.storchaka

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue22123>
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