[issue19164] Update uuid.UUID TypeError exception: integer should not be an argument.
Vajrasky Kok
report at bugs.python.org
Fri Oct 4 15:01:10 CEST 2013
Vajrasky Kok added the comment:
The exception message is correct. You can give an integer argument. But you have to use keyword argument.
>>> uuid.UUID(int=uuid.uuid4().int)
UUID('62ad61e5-b492-4f01-81e6-790049051c4f')
>From the documentation:
__init__(self, hex=None, bytes=None, bytes_le=None, fields=None, int=None, v
ersion=None)
| Create a UUID from either a string of 32 hexadecimal digits,
| a string of 16 bytes as the 'bytes' argument, a string of 16 bytes
| in little-endian order as the 'bytes_le' argument, a tuple of six
| integers (32-bit time_low, 16-bit time_mid, 16-bit time_hi_version,
| 8-bit clock_seq_hi_variant, 8-bit clock_seq_low, 48-bit node) as
| the 'fields' argument, or a single 128-bit integer as the 'int'
| argument. When a string of hex digits is given, curly braces,
| hyphens, and a URN prefix are all optional. For example, these
| expressions all yield the same UUID:
----------
nosy: +vajrasky
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<http://bugs.python.org/issue19164>
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