[issue12548] Add suport native Functor

[Ezio Melotti]

Ezio Melotti <ezio.melotti at gmail.com> added the comment:

Using the func%(args) syntax is not possible because
fab = foo%(1,2)
is equivalent to
fab = foo.__mod__((1,2))

It might actually be possible to overload the % operator to make something that looks like your proposed syntax (without changing the actual Python syntax), but it still look hackish to me.
(We are also moving away from the % overload used by strings for the formatting in favor of the .format() method.)

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