[issue6830] Some uniformness in defaultdict

[Georg Brandl]

Georg Brandl <georg at python.org> added the comment:

This won't change -- the argument of defaultdict is simply a callable
that is called with no arguments and returns the default value.

It works with `int` because `int()` can be called without arguments and
yields 0; however, `defaultdict` cannot.  Therefore, the lambda
expression you wrote is one of the correct ways to spell this.

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nosy: +georg.brandl
resolution:  -> wont fix
status: open -> closed

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