[issue5169] Default hash not equal to id on AMD Sempron

[Mark Dickinson]

Mark Dickinson <dickinsm at gmail.com> added the comment:

It looks like this is a platform with sizeof(long) == 4 and sizeof(void *) 
== 8.  Is that right?  As Antoine says, I can't see any problem here.  Why 
do you think that hash(a) should be equal to id(a) in this case?

Antoine, in what way would id()/4 be better than id()?

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nosy: +marketdickinson

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Python tracker <report at bugs.python.org>
<http://bugs.python.org/issue5169>
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