[ python-Bugs-1289118 ] timedelta multiply and divide by floating point

SourceForge.net noreply at sourceforge.net
Mon Sep 12 23:41:10 CEST 2005


Bugs item #1289118, was opened at 2005-09-12 14:41
Message generated for change (Tracker Item Submitted) made by Item Submitter
You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1289118&group_id=5470

Please note that this message will contain a full copy of the comment thread,
including the initial issue submission, for this request,
not just the latest update.
Category: Python Library
Group: None
Status: Open
Resolution: None
Priority: 5
Submitted By: Daniel Stutzbach (agthorr)
Assigned to: Nobody/Anonymous (nobody)
Summary: timedelta multiply and divide by floating point

Initial Comment:
In python 2.4.1, the datetime.timedelta type allows for
the multiplication and division by integers.  However,
it raises a TypeError for multiplication or division by
floating point numbers.  This is a counterintutive
restriction and I can't think of any good reason for it.

For example:

>>> import datetime
>>> datetime.timedelta(minutes=5)/2
datetime.timedelta(0, 150)
>>> datetime.timedelta(minutes=5)*0.5
Traceback (most recent call last):
  File "<stdin>", line 1, in ?
TypeError: unsupported operand type(s) for *:
'datetime.timedelta' and 'float'


----------------------------------------------------------------------

You can respond by visiting: 
https://sourceforge.net/tracker/?func=detail&atid=105470&aid=1289118&group_id=5470


More information about the Python-bugs-list mailing list