[pypy-commit] pypy default: don't release gil for WSAGetLastError()
bdkearns
noreply at buildbot.pypy.org
Wed Apr 23 00:47:23 CEST 2014
Author: Brian Kearns <bdkearns at gmail.com>
Branch:
Changeset: r70877:7185ae6c5812
Date: 2014-04-22 15:46 -0700
http://bitbucket.org/pypy/pypy/changeset/7185ae6c5812/
Log: don't release gil for WSAGetLastError()
diff --git a/rpython/rlib/_rsocket_rffi.py b/rpython/rlib/_rsocket_rffi.py
--- a/rpython/rlib/_rsocket_rffi.py
+++ b/rpython/rlib/_rsocket_rffi.py
@@ -626,7 +626,7 @@
WSAStartup = external('WSAStartup', [rwin32.WORD, lltype.Ptr(WSAData)],
rffi.INT)
- WSAGetLastError = external('WSAGetLastError', [], rffi.INT)
+ WSAGetLastError = external('WSAGetLastError', [], rffi.INT, releasegil=False)
geterrno = WSAGetLastError
# In tests, the first call to GetLastError is always wrong, because error
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