[pypy-commit] pypy default: prefer print as a statement and one more debug print
pjenvey
noreply at buildbot.pypy.org
Wed Aug 14 02:22:35 CEST 2013
Author: Philip Jenvey <pjenvey at underboss.org>
Branch:
Changeset: r66135:ee703e7a6a8a
Date: 2013-08-13 17:18 -0700
http://bitbucket.org/pypy/pypy/changeset/ee703e7a6a8a/
Log: prefer print as a statement and one more debug print
diff --git a/pypy/module/__pypy__/test/test_signal.py b/pypy/module/__pypy__/test/test_signal.py
--- a/pypy/module/__pypy__/test/test_signal.py
+++ b/pypy/module/__pypy__/test/test_signal.py
@@ -28,16 +28,17 @@
import __pypy__, thread, signal, time, sys
def subthread():
+ print('subthread started')
try:
with __pypy__.thread.signals_enabled:
thread.interrupt_main()
for i in range(10):
- print 'x'
+ print('x')
time.sleep(0.1)
except BaseException, e:
interrupted.append(e)
finally:
- print 'subthread stops, interrupted=%r' % (interrupted,)
+ print('subthread stops, interrupted=%r' % (interrupted,))
done.append(None)
# This is normally called by app_main.py
@@ -53,13 +54,13 @@
try:
done = []
interrupted = []
- print '--- start ---'
+ print('--- start ---')
thread.start_new_thread(subthread, ())
for j in range(10):
if len(done): break
- print '.'
+ print('.')
time.sleep(0.1)
- print 'main thread loop done'
+ print('main thread loop done')
assert len(done) == 1
assert len(interrupted) == 1
assert 'KeyboardInterrupt' in interrupted[0].__class__.__name__
@@ -80,7 +81,7 @@
def threadfunction():
pid = fork()
if pid == 0:
- print 'in child'
+ print('in child')
# signal() only works from the 'main' thread
signal.signal(signal.SIGUSR1, signal.SIG_IGN)
os._exit(42)
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