[Numpy-discussion] Any interest in a 'heaviside' ufunc?
Aron Ahmadia
aron at ahmadia.net
Tue Feb 3 23:41:30 EST 2015
> This is not correct. The discrete form of the Heaviside step function has
> the value 1 for x == 0.
>
Yeah, I was looking at it and wondering if I'd misremembered the
definition. Assuming you're implementing the discrete Heaviside function,
H[0] = 1 as Sturla notes.
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