[Numpy-discussion] Behavior of nan{max, min} and nanarg{max, min} for all-nan slices.

[josef.pktd at gmail.com]

On Wed, Oct 2, 2013 at 2:05 PM, Stéfan van der Walt <stefan at sun.ac.za> wrote:
> On 2 Oct 2013 19:14, "Benjamin Root" <ben.root at ou.edu> wrote:
>>
>> And it is logically consistent, I think.  a[nanargmax(a)] == nanmax(a)
>> (ignoring the silly detail that you can't do an equality on nans).
>
> Why do you call this a silly detail? It seems to me a fundamental flaw to
> this approach.

a nan is a nan is a NaN

>>> np.testing.assert_equal([0, np.nan], [0, np.nan])
>>>

Josef

>
> Stéfan
>
>
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