[Numpy-discussion] finding nonzero elements in list
josef.pktd at gmail.com
josef.pktd at gmail.com
Mon Oct 12 10:36:09 EDT 2009
On Mon, Oct 12, 2009 at 10:18 AM, per freem <perfreem at gmail.com> wrote:
> hi all,
>
> i'm trying to find nonzero elements in an array, as follows:
>
> a = array([[1, 0],
> [1, 1],
> [1, 1],
> [0, 1]])
>
> i want to find all elements that are [1,1]. i tried: nonzero(a ==
> [1,0]) but i cannot interpret the output. the output i get is:
> (array([0, 0, 1, 2]), array([0, 1, 0, 0]))
>
> i simply want to find the indices of the elements that equal [1,0].
> how can i do this? thanks.
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a == [1,0] does elementwise comparison, you need to aggregate
condition for all elements of row
>>> a = np.array([[1, 0],
[1, 1],
[1, 1],
[0, 1]])
>>> np.nonzero((a==[1,0]).all(1))
(array([0]),)
>>> np.where((a==[1,0]).all(1))
(array([0]),)
>>> np.nonzero((a==[1,1]).all(1))
(array([1, 2]),)
Josef
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