[Numpy-discussion] why does b[:-0] not work, and is there an elegant solution?

[Sebastian Walter]

I'm sure there is a better solution....:

In [1]: x = numpy.array([i for i in range(10)])

In [2]:  foo = lambda n: -n if n!=0 else None
   ....:

In [3]: x[:foo(1)]
Out[3]: array([0, 1, 2, 3, 4, 5, 6, 7, 8])

In [4]: x[:foo(0)]
Out[4]: array([0, 1, 2, 3, 4, 5, 6, 7, 8, 9])



On Wed, Aug 19, 2009 at 2:25 PM, Mark Bakker<markbak at gmail.com> wrote:
> Hello list,
>
> I compute the index of the last term in an array that I need and call the
> index n.
>
> I can then call the array b as
>
> b[:-n]
>
> If I need all terms in the array, the logical syntax would be:
>
> b[:-0]
>
> but that doesn't work. Any reason why that has not been implemented? Any
> elegant workaround?
>
> Thanks, Mark
>
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