[Numpy-discussion] Question about numpy.max(<complex matrix>)

[David Goldsmith]

In reply to your reply (which I inadvertently deleted  :-[ ) to my reply:

Point well-made and taken. :-)

DG

Stuart Brorson wrote:
>> No. It is a matter of sorting first on the real part, and then resolving
>> duplicates by sorting on the imaginary part.  The magnitude is not used:
>>     
> [snip]
>
> Oh, OK.  So the ordering algorithm for complex numbers is:
>
> 1.  First sort on real part.
> 2.  Then sort on imag part.
>
> Right?
>
> Stuart
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