[Numpy-discussion] adding field to rec array
John Hunter
jdh2358 at gmail.com
Fri Oct 5 14:02:00 EDT 2007
On 9/26/07, Robert Kern <robert.kern at gmail.com> wrote:
> Here is the straightforward way:
>
> In [15]: import numpy as np
>
> In [16]: dt = np.dtype([('foo', int), ('bar', float)])
>
> In [17]: r = np.zeros((3,3), dtype=dt)
Here is a (hopefully) simple question. If I create an array like
this, how can I efficiently convert it to a record array which lets me
do r.attr in addition to r['attr']. I'm pretty addicted to the former
syntax.
In [114]: dt = np.dtype([('foo', int), ('bar', float)])
In [115]: r = np.zeros((3,3), dtype=dt)
In [116]: r.dtype
Out[116]: dtype([('foo', '<i4'), ('bar', '<f8')])
In [117]: r['foo']
Out[117]:
array([[0, 0, 0],
[0, 0, 0],
[0, 0, 0]])
In [118]: r.foo
------------------------------------------------------------
Traceback (most recent call last):
File "<ipython console>", line 1, in ?
AttributeError: 'numpy.ndarray' object has no attribute 'foo'
Thanks,
JDH
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