[Numpy-discussion] A bug in scipy.linalg.lu_factor?
Paulo J. S. Silva
pjssilva at ime.usp.br
Thu Jan 25 13:06:23 EST 2007
Hello,
I am trying to write some unit tests to my new "Automatic matrix" code
and I think I bumped into a bug in scipy.linalg.lu_factor. If you give a
matrix to it, it doesn't honor the overwrite_a option:
In [1]:import numpy as num
In [2]:M = num.mat(num.random.rand(2,2))
In [3]:print M
[[ 0.33267781 0.2100424 ]
[ 0.61852696 0.32244386]]
In [4]:import scipy.linalg as la
In [5]:LU, P = la.lu_factor(M, overwrite_a=0); print M
[[ 0.33267781 0.63136882]
[ 0.61852696 -0.06807478]]
In [6]:LU, P = la.lu_factor(M, overwrite_a=0); print M
[[ 0.63136882 0.52691517]
[-0.06807478 0.6543966 ]]
As you can see the matrix is changed by calling the function.
can anyone confirm this? I am running numpy 1.0.1 and scipy 0.5.2.
Best,
Paulo
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