[Numpy-discussion] trivial question: how to compare dtype - but ignoring byteorder ?

[Travis Oliphant]

Sebastian Haase wrote:
> Hi,
> if I have a numpy array 'a'
> and say:
> a.dtype == numpy.float32
>
> Is the result independent of a's byteorder ?
> (That's what I would expect ! Just checking !)
>   

I think I misread the question and saw "==" as "="

But, the answer I gave should still help:  the byteorder is a property 
of the data-type.  There is no such thing as "a's" byteorder.   Thus, 
numpy.float32 (which is actually an array-scalar and not a true 
data-type) is interepreted  as a machine-byte-order IEEE floating-point 
data-type with 32 bits.   Thus, the result will depend on whether or not 
a.dtype is machine-order or not.

-Travis