[New-bugs-announce] [issue45542] Using multiple comparison operators can cause performance issues
Maja
report at bugs.python.org
Wed Oct 20 14:25:33 EDT 2021
New submission from Maja <mavioko7 at gmail.com>:
For example:
def f(x):
return 1 < x < 3
will be slower than:
def f(x):
return 1 < x and x < 3
The first function will generate following bytecode:
0 LOAD_CONST 1 (1)
2 LOAD_FAST 0 (x)
4 DUP_TOP
6 ROT_THREE
8 COMPARE_OP 0 (<)
10 JUMP_IF_FALSE_OR_POP 18
12 LOAD_CONST 2 (3)
14 COMPARE_OP 0 (<)
16 RETURN_VALUE
>> 18 ROT_TWO
20 POP_TOP
22 RETURN_VALUE
Performs unnecessary stack operations: duplicates x, rotates 3 items for no reason, then re-rotates 2 items and pops a value. This is fine if the value in the middle was more complex and needed to be duplicated rather than recalculated, which would be definitely slower, but for simpler values like names or constants, it's actually bad. The bytecode for the first function should look the same as second one which is:
0 LOAD_CONST 1 (1)
2 LOAD_FAST 0 (x)
4 COMPARE_OP 0 (<)
6 JUMP_IF_TRUE_OR_POP 14
8 LOAD_FAST 0 (x)
10 LOAD_CONST 2 (3)
12 COMPARE_OP 0 (<)
>> 14 RETURN_VALUE
----------
components: Interpreter Core
messages: 404508
nosy: akuvfx
priority: normal
severity: normal
status: open
title: Using multiple comparison operators can cause performance issues
type: performance
versions: Python 3.11
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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue45542>
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