[New-bugs-announce] [issue43066] Zipfile with leading slashes

[Garrison Taylor]

New submission from Garrison Taylor <garrison.taylor at gridunity.com>:

Currently the zipfile library allows you to create invalid zip files. The following code is an example:

from zipfile import ZipFile
import tempfile
temporary_file = tempfile.NamedTemporaryFile()
my_zip = ZipFile(temporary_file.name, 'w')
my_zip.writestr('/some_folder/some_file.txt', 'Some content')
my_zip.close()

The generated zipfile contains "/some_folder/some_file.txt". However, according to the specification for zip files, this is invalid. See below, from the .ZIP File Format Specification version 6.3.9:

       4.4.17.1 The name of the file, with optional relative path.
       The path stored MUST NOT contain a drive or
       device letter, or a leading slash.  All slashes
       MUST be forward slashes '/' as opposed to
       backwards slashes '\' for compatibility with Amiga
       and UNIX file systems etc.  If input came from standard
       input, there is no file name field.  

This is significant because the default Windows Explorer zip file extractor cannot handle zip files that contain a leading slash, producing an error that "The compressed (zipped) folder is invalid."

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components: Library (Lib)
messages: 385934
nosy: garrison.taylor
priority: normal
severity: normal
status: open
title: Zipfile with leading slashes
type: behavior
versions: Python 3.9

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue43066>
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