[New-bugs-announce] [issue43021] Unpacking tuple argument in combination with inline if statement

[Wietse Jacobs]

New submission from Wietse Jacobs <wietse.j at gmail.com>:

I suspect that I found a bug. If I run the following script:

```
def f(t=None):
    t0, t1 = t if t is not None else [], []
    return t0, t1


def g(t=None):
    if t is None:
        t = [], []
    t0, t1 = t
    return t0, t1


def test():
    res_f = f(t=([1, 1], [2, 2]))
    res_g = g(t=([1, 1], [2, 2]))
    assert res_f == res_g, f'{res_f=} != {res_g=}'


test()
```

I get an assertion error, with:

```
res_f=(([1, 1], [2, 2]), []) != res_g=([1, 1], [2, 2])
```

I expected them to be equal.

----------
messages: 385607
nosy: wietse.j
priority: normal
severity: normal
status: open
title: Unpacking tuple argument in combination with inline if statement
type: behavior
versions: Python 3.9

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Python tracker <report at bugs.python.org>
<https://bugs.python.org/issue43021>
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