[MATRIX-SIG] hash() function w/ NumPy
Hoon Yoon - IPT Quant
hyoon@nyptsrv1.etsd.ml.com
Fri, 25 Jul 1997 12:54:47 -0400
div_prj =3D []
id_lst =3D []
for i in range(0,len(prj_divs),1):
div_spstr =3D string.split(prj_divs[i])
id =3D div_spstr[3]
=04 if not id_lst.count(id): id_lst.append(id)
=09
div_prj.append([id_lst.index(id),chkdate(div_spstr[0]),eval(div_spstr[1])=
])
div_prj =3D array(div_prj)
Thank Aaron:
Here's something I came up with. Basically a similar idea, but it =
keeps
list of id_lst, which I can be pointed right back by the array =
div_prj.
This is not horribly bad, since it does do what I wanted with out =
reverse
of hash. I guess, I need to come up with Qstrategy for comparing =
indicies
from 2 matricies and print function that grabs original names back, =
etc...
=20
I am still unused to the idea that Python could pretty much do =
anything.
I can probably class these things and get back something extremely =
similar,
but better than Gauss's way of handling stuff. Although result may be =
bit
slower than single purpose Gauss, I can be much more creative.
=20
'till I see you,
Hoon,
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