From mustapha.adamu at monash.edu  Fri May  3 02:53:17 2019
From: mustapha.adamu at monash.edu (Mustapha Adamu)
Date: Fri, 3 May 2019 16:53:17 +1000
Subject: [Matplotlib-users] Matplotlib-plotting-based on different condions
 from different maps
Message-ID: <CAC=0njic0juu6VMQSyKUgYjvYMVTVxtrZqdixt=0piGv_ZdqRQ@mail.gmail.com>

Dear all,
I need some help with regards to colormaps, I am new to python and unsure
how to go about it.

I have three spatial correlation maps, lets call the A(72x144), B(72X144)
and C(72x144) and each one of these are made of of values from -1 to 1.

Now I want to generate one single colomap form these based on the following
conditions,

For regions where A > 0.5, B > 0.5 and C > 0.5, make those regions red on
the new color map, for regions where A>0.5, B = 0 and C = 0 also make those
regions Blue.

In a coding format I want something like this
For in range(x):
  for J in range(y):
     if A(i,j) >0 & if B(i,J) > 0.5 & if C>0.5:
       then colormap = Reds.
This is the general idea I have but dont know how to write this and make it
actually work with my code.
I am open to anwer further questions and I would be most grateful for your
help.

Thanks
Adam.
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From jklymak at uvic.ca  Fri May  3 10:39:43 2019
From: jklymak at uvic.ca (Jody Klymak)
Date: Fri, 3 May 2019 07:39:43 -0700
Subject: [Matplotlib-users] Matplotlib-plotting-based on different
 condions from different maps
In-Reply-To: <CAC=0njic0juu6VMQSyKUgYjvYMVTVxtrZqdixt=0piGv_ZdqRQ@mail.gmail.com>
References: <CAC=0njic0juu6VMQSyKUgYjvYMVTVxtrZqdixt=0piGv_ZdqRQ@mail.gmail.com>
Message-ID: <FE61E93C-2512-4F3A-BACD-4EB89B8B676C@uvic.ca>

Hi Adam,

Have a look at `BoundaryNorm` i.e.: https://matplotlib.org/tutorials/colors/colormapnorms.html#discrete-bounds.  Feel free to ask further if you have issues with that.  

However, for your case, you may just want to use pcolormesh and just set the color argument directly.  

Cheers,   Jody

> On May 2, 2019, at  23:53 PM, Mustapha Adamu via Matplotlib-users <matplotlib-users at python.org> wrote:
> 
> Dear all,
> I need some help with regards to colormaps, I am new to python and unsure how to go about it. 
> 
> I have three spatial correlation maps, lets call the A(72x144), B(72X144) and C(72x144) and each one of these are made of of values from -1 to 1. 
> 
> Now I want to generate one single colomap form these based on the following conditions,
> 
> For regions where A > 0.5, B > 0.5 and C > 0.5, make those regions red on the new color map, for regions where A>0.5, B = 0 and C = 0 also make those regions Blue.
> 
> In a coding format I want something like this
> For in range(x):
>   for J in range(y):
>      if A(i,j) >0 & if B(i,J) > 0.5 & if C>0.5:
>        then colormap = Reds.
> This is the general idea I have but dont know how to write this and make it actually work with my code.
> I am open to anwer further questions and I would be most grateful for your help.
> 
> Thanks
> Adam.
> 
> 
> 
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users


From akkana at shallowsky.com  Fri May  3 21:09:08 2019
From: akkana at shallowsky.com (Akkana Peck)
Date: Fri, 3 May 2019 19:09:08 -0600
Subject: [Matplotlib-users] Autoscaling Date Locator with minor ticks?
Message-ID: <20190504010908.GA9339@shallowsky.com>

Is there any way to get AutoDateLocator to handle minor ticks as
well as major ones?

For instance, if I have a plot spanning a few days, I'd like to be
able to show the date as a label and major tick, but show minor
ticks for hours, or one minor tick every six hours, whatever is
sensible depending on the scale. Or on a plot spanning a few years,
show labels for each year, but with 12 minor ticks showing months.
It seems like AutoDateLocator only draws major ticks.

I can write a custom date locator that handles the minor ticks
nicely, but then I don't get the nice auto-scaling of
AutoDateLocator, and if I plot a larger or smaller date range,
my labels and ticks become too crowded or too sparse.

I tried setting both major and minor locators to AutoDateLocators:
    ax.xaxis.set_major_locator(AutoDateLocator())
    ax.xaxis.set_minor_locator(AutoDateLocator())
and similarly with set_*_formatter(), but that just gave me
smeary-looking double-printed major labels and ticks.

Maybe I need to write a custom smart locator that reproduces
AutoDateLocator's auto-scaling while also handling ticks. But before
I dive into that, I thought I'd ask; I can't be the only person who
needs more precise ticks and labeling than AutoDateLocator provides.

Thanks!

        ...Akkana

From mustapha.adamu at monash.edu  Sun May  5 05:15:59 2019
From: mustapha.adamu at monash.edu (Mustapha Adamu)
Date: Sun, 5 May 2019 19:15:59 +1000
Subject: [Matplotlib-users] Making color maps with ranges:
Message-ID: <CAC=0njgV4c2wvAm0wVPbQ7dQcQTcNvYqxWtqtYU3PWC98wQXOA@mail.gmail.com>

Dear all,
I am try to make my own colormap, after searching online including stack
overflow  there is still no luck hence hope to get some help here,

Specifically can I devise my own cmap such that from 1-0.5 is red, 0.5-0.25
is blue, 0.25- -0.25 is white, then -0.25- -0.5 green, and last -0.5- -1 is
blue

My data is 2D spatial data with range -1 to 1
Thanks in ad
Cheers,

*Mustapha Adamu*
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From emilia.petrisor at gmail.com  Sun May  5 12:18:41 2019
From: emilia.petrisor at gmail.com (empet)
Date: Sun, 5 May 2019 09:18:41 -0700 (MST)
Subject: [Matplotlib-users] Making color maps with ranges:
In-Reply-To: <CAC=0njgV4c2wvAm0wVPbQ7dQcQTcNvYqxWtqtYU3PWC98wQXOA@mail.gmail.com>
References: <CAC=0njgV4c2wvAm0wVPbQ7dQcQTcNvYqxWtqtYU3PWC98wQXOA@mail.gmail.com>
Message-ID: <1557073121119-0.post@n5.nabble.com>

matplotlib - users mailing list wrote
> Dear all,
> I am try to make my own colormap, after searching online including stack
> overflow  there is still no luck hence hope to get some help here,
> 
> Specifically can I devise my own cmap such that from 1-0.5 is red,
> 0.5-0.25
> is blue, 0.25- -0.25 is white, then -0.25- -0.5 green, and last -0.5- -1
> is
> blue
> 
> My data is 2D spatial data with range -1 to 1
> Thanks in ad
> Cheers,
> 
> *Mustapha Adamu*
> 
> _______________________________________________
> Matplotlib-users mailing list

> Matplotlib-users@

> https://mail.python.org/mailman/listinfo/matplotlib-users

Mustapha,

You should define a discrete colormap as follows:

boundaries = [-1, -0.5, -0.25, 0.25, 0.5, 1]  
cmap= colors.ListedColormap(['blue', 'green','white', 'blue', 'red'])
norm = colors.BoundaryNorm(boundaries, cmap.N, clip=True)

Then the following code:

x = np.linspace(0, np.pi, 400)
x, y = np.meshgrid(x, x)
z = np.sin(x*y)
plt.pcolormesh(x, y, z, cmap=cmap, norm=norm)
plt.colorbar()

generates an image as you wanted:

<http://matplotlib.1069221.n5.nabble.com/file/t4189/rsz_1sinxy.png> 



--
Sent from: http://matplotlib.1069221.n5.nabble.com/matplotlib-users-f3.html

From cgiusti at udel.edu  Wed May  8 13:02:23 2019
From: cgiusti at udel.edu (cgiusti)
Date: Wed, 8 May 2019 10:02:23 -0700 (MST)
Subject: [Matplotlib-users] 3d plotting issue
Message-ID: <1557334943465-0.post@n5.nabble.com>

Dear matplotlib users,

I've encountered an issue with 3d plotting that has me completely stumped.
Since a recent update that added ipympl, any plot that uses projection='3d'
is completely incorrect, even after subsequently removing the package. For
example, running the sample parametric line plot code from the mplot3d
tutorial located at

https://matplotlib.org/mpl_examples/mplot3d/lines3d_demo.py

produces the following image

<http://matplotlib.1069221.n5.nabble.com/file/t5232/parametric_error.png> 

Each of the plots looks vaguely like the points being used to generate the
plot are sent to random locations, and clearly the axis is upside down --
possibly an error when computing the projection? 2D plotting works as
expected, as do other aspects of the package. Any assistance or suggestions
(including other places to ask) would be helpful.

Details: I have a group of users working in a JupyterHub (0.9.6) environment
on a local Ubuntu 17.10 server. The hub uses SystemUserSpawner to create
local Docker containers running JupyterLab (0.35.6) environments for
individual users. The containers run Ubuntu 17.10, Python 3.6.7 and
matplotlib 3.0.3. Plotting was working fine until I recently updated the
Docker images to include ipympl to allow the users to make interactive 3d
plots. 

Once the issue above became apparent, I rolled back the dockerfile to the
previous, working version (rebuilt using --nocache), but the problem
persists. I have  built a bare-bones version of the container which includes
only the OS packages, python, the current conda versions of notebook,
jupyterhub, jupyterlab, and matplotlib, and the problem persists. This
minimal Dockerfile is available here:

https://www.dropbox.com/s/h3fuej3higaws0r/Dockerfile.min?dl=0

Because it persists across container rebuilds, my best guess is that adding
ipympl created or modified a file in the users' home directories, as these
are the only directories visible to the containers. 

I'm happy to provide more detailed information, but don't want to dump
things that won't be useful.

Thanks for your attention,
Chad



--
Sent from: http://matplotlib.1069221.n5.nabble.com/matplotlib-users-f3.html

From niklas.berliner at gmail.com  Thu May  9 07:17:17 2019
From: niklas.berliner at gmail.com (Niklas Berliner)
Date: Thu, 9 May 2019 12:17:17 +0100
Subject: [Matplotlib-users] Hexbin plot,
 PolyCollection and inconsistent facecolor values
In-Reply-To: <CAJ4spfvHXW6Z2RGqv5M+ZverTmEWGehzeWSePpBw+2zhqYid8Q@mail.gmail.com>
References: <CAJ4spfvHXW6Z2RGqv5M+ZverTmEWGehzeWSePpBw+2zhqYid8Q@mail.gmail.com>
Message-ID: <CAJ4spfu7ysEa3UG_nwxo9ugk1LxRUojv1dXiVHkLPC2Su+ECwg@mail.gmail.com>

Just a quick update in case somebody else has a similar problem.

I needed to call plt.draw() within the Jupyter Notebook cell to populate
the polycollection, that is, directly after the plt.hexhin() call and
before the print() statement.

Cheers,
Niklas

On Tue, 30 Apr 2019 at 10:02, Niklas Berliner <niklas.berliner at gmail.com>
wrote:

> Hi,
>
> I am trying to change the edgecolor of some hexbin patches in a hexbin
> plot. Fiddling around with it to understand how this could work, I
> encountered a behaviour I cannot understand. I initially opened an issue at
> seaborn here https://github.com/mwaskom/seaborn/issues/1734 . I get the
> same behaviour with pure matplotlib and am now asking here for help.
>
> Calling get_facecolors() on the PolyCollection returned by plt.hexbin
> gives different results depending on the jupyter notebook cell within which
> the call is made.
>
> Here's my example (assuming the code is run in a notebook, using Python
> 3.6.8, NumPy 1.16.2, Matplotlib 3.0.3, Jupyter 4.4.0)
>
> Cell 1:
> -------
> import matplotlib
> import matplotlib.pyplot as plt
> import numpy as np
> -------
>
> Cell 2:
> -------
> x = np.array([1,1,1,1.5,1.5,2])
> y = np.array([1,1,1,1,1,1])
> -------
>
> Cell 3:
> -------
> polycollection = plt.hexbin(x, y, C=np.ones(x.shape),
> reduce_C_function=np.sum, extent=[1, 2, 0.5, 1.5], gridsize=3,
> linewidths=1, edgecolors='face')
> print(polycollection.get_facecolors())
> -------
> This plots three hexbins with different counts and different colours.
> Here, get_facecolors() returns a (1,4) array, namely,
> [[0.12156863 0.46666667 0.70588235 1.        ]]
>
> Cell 4:
> -------
> print(polycollection.get_facecolors())
> -------
> When calling get_facecolors() again in the next cell, a (3,4) array is
> returned, namely,
> [[0.993248 0.906157 0.143936 1.      ]
>  [0.127568 0.566949 0.550556 1.      ]
>  [0.267004 0.004874 0.329415 1.      ]]
>
>
> The second array seems to be the correct one I think (there are different
> colors for each of the three hexbins). What is happening here? I am very
> confused!
>
> Thanks,
> Niklas
>
>
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From jslavin at cfa.harvard.edu  Tue May 14 11:43:44 2019
From: jslavin at cfa.harvard.edu (Slavin, Jonathan)
Date: Tue, 14 May 2019 11:43:44 -0400
Subject: [Matplotlib-users] plot with multiple images and colorbar
Message-ID: <CACcRS=efSva0z+EsuVRBg2snVBNrx9vgEcB1yN=m56iewOGsBg@mail.gmail.com>

Hi,

I've been working on producing a figure using results of a hydro simulation
at multiple times. Because the scale of the region of interest changes over
time, I want the size of the axes to change. My goal is to make a figure
with results of four timesteps, so four images in a row, with each scaled
appropriately and with a colorbar on the right. I tried to use ImageGrid,
but that doesn't like having different axis scales for the plots - at least
it seems to always scale the y axis the same despite my best efforts -
though it does a nice job of locating the colorbar.

So I went back to subplots, but in that case the colorbar isn't the right
size, at least without tweaking the shrink parameter. Also, for some reason
there is a lot of space on the right of the plot even when I use
subplots_adjust to set right=0.99. There are many ways to place colorbars,
I know, but it would seem that my case would not be so unusual that I
should need such complex methods to do what I want. Maybe I'm missing
something. Any advice would be appreciated.

Regards,
Jon

-- 
Jonathan D. Slavin
Astrophysicist - High Energy Astrophysics Division
Center for Astrophysics | Harvard & Smithsonian
Office: (617) 496-7981 | Cell: (781) 363-0035
60 Garden Street | MS 83 | Cambridge, MA 02138
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From jklymak at uvic.ca  Tue May 14 12:02:19 2019
From: jklymak at uvic.ca (Jody Klymak)
Date: Tue, 14 May 2019 09:02:19 -0700
Subject: [Matplotlib-users] plot with multiple images and colorbar
In-Reply-To: <CACcRS=efSva0z+EsuVRBg2snVBNrx9vgEcB1yN=m56iewOGsBg@mail.gmail.com>
References: <CACcRS=efSva0z+EsuVRBg2snVBNrx9vgEcB1yN=m56iewOGsBg@mail.gmail.com>
Message-ID: <D66196A1-BF3A-4C8B-82F0-72125008A8AA@uvic.ca>

Hi Jonathan, 

If you are setting the aspect ratio of your subplots, space can be missing on the RHS if the setting the aspect ratio causes the subplots to shrink horizontally.  The ?solution? to this is to make your *figure* more tall and less wide until the aspect ratio shrink happens in the vertical instead of the horizontal, or don?t set the aspect ratio.  Its pretty hard for matplotlib to do this automatically and still do the usual layout for axes that do not have their aspect ratio set, the desired behaviour of which is to make the axes as big as possible.

I?m working on a PR to make colorbars automatically match the height of the shown axes, rather than its place holder, but thats non-trivial. 

Cheers,  Jody

> On 14 May 2019, at 08:43, Slavin, Jonathan <jslavin at cfa.harvard.edu> wrote:
> 
> Hi,
> 
> I've been working on producing a figure using results of a hydro simulation at multiple times. Because the scale of the region of interest changes over time, I want the size of the axes to change. My goal is to make a figure with results of four timesteps, so four images in a row, with each scaled appropriately and with a colorbar on the right. I tried to use ImageGrid, but that doesn't like having different axis scales for the plots - at least it seems to always scale the y axis the same despite my best efforts - though it does a nice job of locating the colorbar.
> 
> So I went back to subplots, but in that case the colorbar isn't the right size, at least without tweaking the shrink parameter. Also, for some reason there is a lot of space on the right of the plot even when I use subplots_adjust to set right=0.99. There are many ways to place colorbars, I know, but it would seem that my case would not be so unusual that I should need such complex methods to do what I want. Maybe I'm missing something. Any advice would be appreciated.
> 
> Regards,
> Jon
> 
> -- 
> 
> Jonathan D. Slavin
> Astrophysicist - High Energy Astrophysics Division
> Center for Astrophysics | Harvard & Smithsonian
> Office: (617) 496-7981 | Cell: (781) 363-0035
> 60 Garden Street | MS 83 | Cambridge, MA 02138
> 
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users

--
Jody Klymak    
http://web.uvic.ca/~jklymak/





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From jslavin at cfa.harvard.edu  Tue May 14 12:59:40 2019
From: jslavin at cfa.harvard.edu (Slavin, Jonathan)
Date: Tue, 14 May 2019 12:59:40 -0400
Subject: [Matplotlib-users] plot with multiple images and colorbar
In-Reply-To: <D66196A1-BF3A-4C8B-82F0-72125008A8AA@uvic.ca>
References: <CACcRS=efSva0z+EsuVRBg2snVBNrx9vgEcB1yN=m56iewOGsBg@mail.gmail.com>
 <D66196A1-BF3A-4C8B-82F0-72125008A8AA@uvic.ca>
Message-ID: <CACcRS=fiGfXVOBJEhU7h2JA_oRvQZ9ENJpwriuM0ObTYDaGb2w@mail.gmail.com>

Hi Jody,

I'm not explicitly setting the aspect ratio. It's set, I think, by the
shape of the images that are plotted via imshow. Yes, I'd like for the
height of the colorbar to match that of the plots. I am able to get it to
do that by changing the shape of the plotting window, but it'd be nicer if
it worked without having to do that.

It all looks good and works as desired when I use ImageGrid and the axis
limits are all the same, but if I try to use  different ylimits then things
go wrong - even with images that have the same aspect ratio.

Jon

On Tue, May 14, 2019 at 12:02 PM Jody Klymak <jklymak at uvic.ca> wrote:

> Hi Jonathan,
>
> If you are setting the aspect ratio of your subplots, space can be missing
> on the RHS if the setting the aspect ratio causes the subplots to shrink
> horizontally.  The ?solution? to this is to make your *figure* more tall
> and less wide until the aspect ratio shrink happens in the vertical instead
> of the horizontal, or don?t set the aspect ratio.  Its pretty hard for
> matplotlib to do this automatically and still do the usual layout for axes
> that do not have their aspect ratio set, the desired behaviour of which is
> to make the axes as big as possible.
>
> I?m working on a PR to make colorbars automatically match the height of
> the shown axes, rather than its place holder, but thats non-trivial.
>
> Cheers,  Jody
>
> On 14 May 2019, at 08:43, Slavin, Jonathan <jslavin at cfa.harvard.edu>
> wrote:
>
> Hi,
>
> I've been working on producing a figure using results of a hydro
> simulation at multiple times. Because the scale of the region of interest
> changes over time, I want the size of the axes to change. My goal is to
> make a figure with results of four timesteps, so four images in a row, with
> each scaled appropriately and with a colorbar on the right. I tried to use
> ImageGrid, but that doesn't like having different axis scales for the plots
> - at least it seems to always scale the y axis the same despite my best
> efforts - though it does a nice job of locating the colorbar.
>
> So I went back to subplots, but in that case the colorbar isn't the right
> size, at least without tweaking the shrink parameter. Also, for some reason
> there is a lot of space on the right of the plot even when I use
> subplots_adjust to set right=0.99. There are many ways to place colorbars,
> I know, but it would seem that my case would not be so unusual that I
> should need such complex methods to do what I want. Maybe I'm missing
> something. Any advice would be appreciated.
>
> Regards,
> Jon
>
> --
> Jonathan D. Slavin
> Astrophysicist - High Energy Astrophysics Division
> Center for Astrophysics | Harvard & Smithsonian
> Office: (617) 496-7981 | Cell: (781) 363-0035
> 60 Garden Street | MS 83 | Cambridge, MA 02138
>
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users
>
>
> --
> Jody Klymak
> http://web.uvic.ca/~jklymak/
>
>
>
>
>
>

-- 
Jonathan D. Slavin
Astrophysicist - High Energy Astrophysics Division
Center for Astrophysics | Harvard & Smithsonian
Office: (617) 496-7981 | Cell: (781) 363-0035
60 Garden Street | MS 83 | Cambridge, MA 02138
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From diego.avesani at gmail.com  Wed May 15 06:20:54 2019
From: diego.avesani at gmail.com (Diego Avesani)
Date: Wed, 15 May 2019 12:20:54 +0200
Subject: [Matplotlib-users] double x-axis with defined xtick and inverse
 order
Message-ID: <CAG8o1y5AybdEpohU+j2KjDPKKP6mTXANLFjkgTV=NxVu+ezKBg@mail.gmail.com>

Dear all,

I would like to plot a figure with double x-axes.
Unfortunately, it seems the ticks of the second x axis do not fit with what
I want.

Here the example:

import numpy as np
import matplotlib.pyplot as plt

MM = np.array([ 1.,  2.,  4.,  8., 16., 32.])
SS = np.array([64., 32., 16.,  8.,  4.,  2.])
RR = np.array([2813, 1544,  895,  562,  459,409])

ax = plt.subplot(111)
ax.grid(True,which="both",ls="-",color='0.6')
ax.plot(MM, RR  ,'-r')

ax2 = ax.twiny()
ax2.invert_xaxis()
ax2.plot(MM, RR, 'none')
ax2.set_xticks([64,32,16,8,4,2])
ax2.set_xticklabels(['64','32','16','8','4','2'])
plt.show()

As it can be noticed, the value 32 in the ax2 does not correspond to the
second value but is put in the middle point of ax2. I would like to have it
in the same vertical line of the second value of MM.  This of course not
only for 32 but for the value in SS. Basically I would like to have the
main axis according to MM and a second ax with SS value in the same line of
MM values.

I hope I made myself clear.

really really thanks and,
best regards

Diego
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From filip at ownit.nu  Fri May 17 05:19:26 2019
From: filip at ownit.nu (FilipPersson)
Date: Fri, 17 May 2019 02:19:26 -0700 (MST)
Subject: [Matplotlib-users] Matplotlib plots display as blank in interactive
 mode with no error messages - (one) Solution
Message-ID: <1558084766050-0.post@n5.nabble.com>

I spent several hours googling and trying myself to change my code to fix
this. No luck in googling and the fact that there was a kind of doing brain
surgery on Matplotlib by uninstall, re-install and update and change backend
library for a similar but not quite the same problem made me think that I
should post the solution somewhere since it was almost impossible to spot.

If you get plots like this:
<http://matplotlib.1069221.n5.nabble.com/file/t5236/Blank_plot.png> 
Which, as you see gives no error output - not even when clicking on the
graph. Actually, nothing at all happens when clicking on the graph.
Interactivity is lost.

It could be a LaTeX problem causing it!
The reason for the blank plot was that I had used a LaTeX escape character
for the value 0 when creating nice labels for the x axis. Apparently, using
'$\0$' to write the number zero in LaTeX makes the plots blank and kills the
interactivity. Restarting the kernel did no good.
If I instead write '$0$' as a label, everything works fine again.

My environment is Mac OSX 10.13.6, Matplotlib 3.0.2, Python 3.7.1, running
in Jupyter (notebook server version 5.7.4, IPython 7.2.0) in Safari Version
12.0 (13606.2.11).

If you want to see my code, please request it and then I will post it.



--
Sent from: http://matplotlib.1069221.n5.nabble.com/matplotlib-users-f3.html

From oren.a4 at gmail.com  Fri May 17 08:51:05 2019
From: oren.a4 at gmail.com (oren)
Date: Fri, 17 May 2019 05:51:05 -0700 (MST)
Subject: [Matplotlib-users] Editable text from matplotlib?
In-Reply-To: <CANNq6F=DmVscB15_FkDjaz_ONhUHKXE0J5_hAoEC+S6KJFi_Kg@mail.gmail.com>
References: <649847CE7F259144A0FD99AC64E7326D12B979@MLBXV17.nih.gov>
 <CA+phhE=A4xKjv7posKzSa0SmU4GY7kpz9RiiRLjBYuiauyC9UQ@mail.gmail.com>
 <9D9A79EA-32CE-403F-839A-EE0E0A0C9DFD@alum.mit.edu>
 <CANNq6F=DmVscB15_FkDjaz_ONhUHKXE0J5_hAoEC+S6KJFi_Kg@mail.gmail.com>
Message-ID: <1558097465121-0.post@n5.nabble.com>

To change teh text form path to text use this line:
matplotlib.rcParams['pdf.fonttype'] = 42

Read more here:
http://physicalmodelingwithpython.blogspot.com/2015/06/making-plots-for-publication.html




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From tcaswell at gmail.com  Fri May 17 09:58:37 2019
From: tcaswell at gmail.com (Thomas Caswell)
Date: Fri, 17 May 2019 09:58:37 -0400
Subject: [Matplotlib-users] Matplotlib plots display as blank in
 interactive mode with no error messages - (one) Solution
In-Reply-To: <1558084766050-0.post@n5.nabble.com>
References: <1558084766050-0.post@n5.nabble.com>
Message-ID: <CAA48SF8u8_7ibhjito5d-9WmdtPyP8aWiiZVJWU7=h84ZOYTkw@mail.gmail.com>

This is possible related to
https://github.com/matplotlib/matplotlib/issues/13988 .  What backend are
you using?

Tom

On Fri, May 17, 2019 at 5:19 AM FilipPersson <filip at ownit.nu> wrote:

> I spent several hours googling and trying myself to change my code to fix
> this. No luck in googling and the fact that there was a kind of doing brain
> surgery on Matplotlib by uninstall, re-install and update and change
> backend
> library for a similar but not quite the same problem made me think that I
> should post the solution somewhere since it was almost impossible to spot.
>
> If you get plots like this:
> <http://matplotlib.1069221.n5.nabble.com/file/t5236/Blank_plot.png>
> Which, as you see gives no error output - not even when clicking on the
> graph. Actually, nothing at all happens when clicking on the graph.
> Interactivity is lost.
>
> It could be a LaTeX problem causing it!
> The reason for the blank plot was that I had used a LaTeX escape character
> for the value 0 when creating nice labels for the x axis. Apparently, using
> '$\0$' to write the number zero in LaTeX makes the plots blank and kills
> the
> interactivity. Restarting the kernel did no good.
> If I instead write '$0$' as a label, everything works fine again.
>
> My environment is Mac OSX 10.13.6, Matplotlib 3.0.2, Python 3.7.1, running
> in Jupyter (notebook server version 5.7.4, IPython 7.2.0) in Safari Version
> 12.0 (13606.2.11).
>
> If you want to see my code, please request it and then I will post it.
>
>
>
> --
> Sent from:
> http://matplotlib.1069221.n5.nabble.com/matplotlib-users-f3.html
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users
>


-- 
Thomas Caswell
tcaswell at gmail.com
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From tcaswell at gmail.com  Sat May 18 15:25:32 2019
From: tcaswell at gmail.com (Thomas Caswell)
Date: Sat, 18 May 2019 15:25:32 -0400
Subject: [Matplotlib-users] REL: Matplotlib 3.1.0
Message-ID: <CAA48SF9i3d6Nt0f3tX+3zX=V-Aj9UYC_S276SrMyk802suqk6A@mail.gmail.com>

Folks,

We are happy to announce the release of Matplotlib 3.1!

Matplotlib 3.1 supports Python 3.6+.

Highlights of this release include:

 - A helper method for scatter legends
 - Secondary axis support (ex, degrees and radians)
 - A concise date formatter
 - No longer requires a framework build of Python to use OSX backend
 - Major and minor ticks will no longer collide by default
 - A progress callback for animations
 - mplot3D is always registered
 - deprecated mlab functions have been removed
 - Many function calls have become stricter about invalid or ignored input

For the full details see
- whats new: https://matplotlib.org/users/whats_new.html
- API changes: https://matplotlib.org/api/api_changes.html

A big thank you to everyone who worked on this release including the 151
people contributed code [1] and the many more who reported issues.

We are planning to have Matplotlib 3.2 released in September/October and
Matplotlib 2.2.5 (the final release of the 2.2.x LTS series) in December.

Tom

[1] https://matplotlib.org/users/github_stats.html

-- 
Thomas Caswell
tcaswell at gmail.com
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From farukerdemoncel at gmail.com  Sat May 18 17:58:46 2019
From: farukerdemoncel at gmail.com (Erdem)
Date: Sun, 19 May 2019 00:58:46 +0300
Subject: [Matplotlib-users] Convolution integral export as animation
Message-ID: <CANY7k6=PFGGeosRqr8bsPGQ2S53KtyV2Ut=anqjEa9SWooVsyQ@mail.gmail.com>

This example is taken from a tutorial
<https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html>
related
to convolution integral.

I would like to export this example as animation in mp4 format. So far, the
code looks like this :

import scipy.integrateimport numpy as npimport matplotlib.pyplot as
pltimport matplotlib.animation as animation
def showConvolution(t0,f1, f2):
    # Calculate the overall convolution result using Simpson integration
    convolution = np.zeros(len(t))
    for n, t_ in enumerate(t):
        prod = lambda tau: f1(tau) * f2(t_-tau)
        convolution[n] = scipy.integrate.simps(prod(t), t)

    # Create the shifted and flipped function
    f_shift = lambda t: f2(t0-t)
    prod = lambda tau: f1(tau) * f2(t0-tau)

    # Plot the curves
    plt.gcf().clear() # il

    plt.subplot(211)
    plt.gca().set_ymargin(0.05) # il
    plt.plot(t, f1(t), label=r'$f_1(\tau)$')
    plt.plot(t, f_shift(t), label=r'$f_2(t_0-\tau)$')
    plt.fill(t, prod(t), color='r', alpha=0.5, edgecolor='black',
hatch='//') # il
    plt.plot(t, prod(t), 'r-', label=r'$f_1(\tau)f_2(t_0-\tau)$')
    plt.grid(True); plt.xlabel(r'$\tau$'); plt.ylabel(r'$x(\tau)$') # il
    plt.legend(fontsize=10) # il
    plt.text(-4, 0.6, '$t_0=%.2f$' % t0, bbox=dict(fc='white')) # il

    # plot the convolution curve
    plt.subplot(212)
    plt.gca().set_ymargin(0.05) # il
    plt.plot(t, convolution, label='$(f_1*f_2)(t)$')

    # recalculate the value of the convolution integral at the current
time-shift t0
    current_value = scipy.integrate.simps(prod(t), t)
    plt.plot(t0, current_value, 'ro')  # plot the point
    plt.grid(True); plt.xlabel('$t$'); plt.ylabel('$(f_1*f_2)(t)$') # il
    plt.legend(fontsize=10) # il
    plt.show() # il
Fs = 50  # our sampling frequency for the plotting
T = 5    # the time range we are interested in
t = np.arange(-T, T, 1/Fs)  # the time samples
f1 = lambda t: np.maximum(0, 1-abs(t))
f2 = lambda t: (t>0) * np.exp(-2*t)

t0 = np.arange(-2.0,2.0, 0.05)

fig = plt.figure(figsize=(8,3))
anim = animation.FuncAnimation(fig, showConvolution, frames=t0,
fargs=(f1,f2),interval=80)

anim.save('animation.mp4', fps=30) # fps = frames per second

plt.show()

Is there a way to change t0 so that I'd like to able to save it as
animation as in the tutorial
<https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html>
In
the example t0 decreases from -2.0 to -1.95 etc the green curve is shifted
right, and the area between curves, product increases. In the tutorial
there is an html animation and I would like to save as mp4 file.

I've also added code as an attachment.
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From farukerdemoncel at gmail.com  Sat May 18 18:05:10 2019
From: farukerdemoncel at gmail.com (Erdem)
Date: Sun, 19 May 2019 01:05:10 +0300
Subject: [Matplotlib-users] Convolution integral export as animation
Message-ID: <CANY7k6n2m03UB1=UOjO8Z30Eja-zd9w9mJQNgWrA7gMfx1vFxw@mail.gmail.com>

This example is taken from a tutorial
<https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html>
related
to convolution integral.

I would like to export this example as animation in mp4 format. So far, the
code looks like this :

import scipy.integrateimport numpy as npimport matplotlib.pyplot as
pltimport matplotlib.animation as animation
def showConvolution(t0,f1, f2):
    # Calculate the overall convolution result using Simpson integration
    convolution = np.zeros(len(t))
    for n, t_ in enumerate(t):
        prod = lambda tau: f1(tau) * f2(t_-tau)
        convolution[n] = scipy.integrate.simps(prod(t), t)

    # Create the shifted and flipped function
    f_shift = lambda t: f2(t0-t)
    prod = lambda tau: f1(tau) * f2(t0-tau)

    # Plot the curves
    plt.gcf().clear() # il

    plt.subplot(211)
    plt.gca().set_ymargin(0.05) # il
    plt.plot(t, f1(t), label=r'$f_1(\tau)$')
    plt.plot(t, f_shift(t), label=r'$f_2(t_0-\tau)$')
    plt.fill(t, prod(t), color='r', alpha=0.5, edgecolor='black',
hatch='//') # il
    plt.plot(t, prod(t), 'r-', label=r'$f_1(\tau)f_2(t_0-\tau)$')
    plt.grid(True); plt.xlabel(r'$\tau$'); plt.ylabel(r'$x(\tau)$') # il
    plt.legend(fontsize=10) # il
    plt.text(-4, 0.6, '$t_0=%.2f$' % t0, bbox=dict(fc='white')) # il

    # plot the convolution curve
    plt.subplot(212)
    plt.gca().set_ymargin(0.05) # il
    plt.plot(t, convolution, label='$(f_1*f_2)(t)$')

    # recalculate the value of the convolution integral at the current
time-shift t0
    current_value = scipy.integrate.simps(prod(t), t)
    plt.plot(t0, current_value, 'ro')  # plot the point
    plt.grid(True); plt.xlabel('$t$'); plt.ylabel('$(f_1*f_2)(t)$') # il
    plt.legend(fontsize=10) # il
    plt.show() # il
Fs = 50  # our sampling frequency for the plotting
T = 5    # the time range we are interested in
t = np.arange(-T, T, 1/Fs)  # the time samples
f1 = lambda t: np.maximum(0, 1-abs(t))
f2 = lambda t: (t>0) * np.exp(-2*t)

t0 = np.arange(-2.0,2.0, 0.05)

fig = plt.figure(figsize=(8,3))
anim = animation.FuncAnimation(fig, showConvolution, frames=t0,
fargs=(f1,f2),interval=80)

anim.save('animation.mp4', fps=30) # fps = frames per second

plt.show()


When I run the program I see the output of see the output of convolution
integral at t0 = -0.20.

[image: convolution.png]

Is there a way to change t0 so that I'd like to able to save it as
animation as in the tutorial
<https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html>
In
the example t0 decreases from -2.0 to -1.95 etc the green curve is shifted
right, and the area between curves, product increases. In the tutorial
there is an html animation and I would like to save as mp4 file.

I've also added source code as an attachment.
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From filip at ownit.nu  Sun May 19 03:50:50 2019
From: filip at ownit.nu (FilipPersson)
Date: Sun, 19 May 2019 00:50:50 -0700 (MST)
Subject: [Matplotlib-users] Matplotlib plots display as blank in
 interactive mode with no error messages - (one) Solution
In-Reply-To: <CAA48SF8u8_7ibhjito5d-9WmdtPyP8aWiiZVJWU7=h84ZOYTkw@mail.gmail.com>
References: <1558084766050-0.post@n5.nabble.com>
 <CAA48SF8u8_7ibhjito5d-9WmdtPyP8aWiiZVJWU7=h84ZOYTkw@mail.gmail.com>
Message-ID: <1558252250113-0.post@n5.nabble.com>

Hi Tom,
I'm not sure if it's related. I'm using nbAgg. It acme automatically when I
installed and I haven't changed it. Their plots go black. Not all my plots
go crazy when I do the escape character error, only the interactive ones
when re-running.



--
Sent from: http://matplotlib.1069221.n5.nabble.com/matplotlib-users-f3.html

From tcaswell at gmail.com  Sun May 19 17:16:48 2019
From: tcaswell at gmail.com (Thomas Caswell)
Date: Sun, 19 May 2019 17:16:48 -0400
Subject: [Matplotlib-users] Convolution integral export as animation
In-Reply-To: <CANY7k6n2m03UB1=UOjO8Z30Eja-zd9w9mJQNgWrA7gMfx1vFxw@mail.gmail.com>
References: <CANY7k6n2m03UB1=UOjO8Z30Eja-zd9w9mJQNgWrA7gMfx1vFxw@mail.gmail.com>
Message-ID: <CAA48SF_8fpq9UFdTHO0x_ECqLhJnRkKi6kBrUMCyeJ7yOmpVRA@mail.gmail.com>

Erdem,

I do not understand your question.  If I run that code I do get an mp4 file
of the animation.

Tom


On Sat, May 18, 2019 at 6:05 PM Erdem <farukerdemoncel at gmail.com> wrote:

> This example is taken from a tutorial
> <https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html> related
> to convolution integral.
>
> I would like to export this example as animation in mp4 format. So far,
> the code looks like this :
>
> import scipy.integrateimport numpy as npimport matplotlib.pyplot as pltimport matplotlib.animation as animation
> def showConvolution(t0,f1, f2):
>     # Calculate the overall convolution result using Simpson integration
>     convolution = np.zeros(len(t))
>     for n, t_ in enumerate(t):
>         prod = lambda tau: f1(tau) * f2(t_-tau)
>         convolution[n] = scipy.integrate.simps(prod(t), t)
>
>     # Create the shifted and flipped function
>     f_shift = lambda t: f2(t0-t)
>     prod = lambda tau: f1(tau) * f2(t0-tau)
>
>     # Plot the curves
>     plt.gcf().clear() # il
>
>     plt.subplot(211)
>     plt.gca().set_ymargin(0.05) # il
>     plt.plot(t, f1(t), label=r'$f_1(\tau)$')
>     plt.plot(t, f_shift(t), label=r'$f_2(t_0-\tau)$')
>     plt.fill(t, prod(t), color='r', alpha=0.5, edgecolor='black', hatch='//') # il
>     plt.plot(t, prod(t), 'r-', label=r'$f_1(\tau)f_2(t_0-\tau)$')
>     plt.grid(True); plt.xlabel(r'$\tau$'); plt.ylabel(r'$x(\tau)$') # il
>     plt.legend(fontsize=10) # il
>     plt.text(-4, 0.6, '$t_0=%.2f$' % t0, bbox=dict(fc='white')) # il
>
>     # plot the convolution curve
>     plt.subplot(212)
>     plt.gca().set_ymargin(0.05) # il
>     plt.plot(t, convolution, label='$(f_1*f_2)(t)$')
>
>     # recalculate the value of the convolution integral at the current time-shift t0
>     current_value = scipy.integrate.simps(prod(t), t)
>     plt.plot(t0, current_value, 'ro')  # plot the point
>     plt.grid(True); plt.xlabel('$t$'); plt.ylabel('$(f_1*f_2)(t)$') # il
>     plt.legend(fontsize=10) # il
>     plt.show() # il
> Fs = 50  # our sampling frequency for the plotting
> T = 5    # the time range we are interested in
> t = np.arange(-T, T, 1/Fs)  # the time samples
> f1 = lambda t: np.maximum(0, 1-abs(t))
> f2 = lambda t: (t>0) * np.exp(-2*t)
>
> t0 = np.arange(-2.0,2.0, 0.05)
>
> fig = plt.figure(figsize=(8,3))
> anim = animation.FuncAnimation(fig, showConvolution, frames=t0, fargs=(f1,f2),interval=80)
>
> anim.save('animation.mp4', fps=30) # fps = frames per second
>
> plt.show()
>
>
> When I run the program I see the output of see the output of convolution
> integral at t0 = -0.20.
>
> [image: convolution.png]
>
> Is there a way to change t0 so that I'd like to able to save it as
> animation as in the tutorial
> <https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html> In
> the example t0 decreases from -2.0 to -1.95 etc the green curve is shifted
> right, and the area between curves, product increases. In the tutorial
> there is an html animation and I would like to save as mp4 file.
>
> I've also added source code as an attachment.
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users
>


-- 
Thomas Caswell
tcaswell at gmail.com
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From tcaswell at gmail.com  Sun May 19 18:05:45 2019
From: tcaswell at gmail.com (Thomas Caswell)
Date: Sun, 19 May 2019 18:05:45 -0400
Subject: [Matplotlib-users] Convolution integral export as animation
In-Reply-To: <CANY7k6=CRaUX+SV6T0MfPtxa5k+VddXcbu9kYRZLFdhrkwgMqw@mail.gmail.com>
References: <CANY7k6n2m03UB1=UOjO8Z30Eja-zd9w9mJQNgWrA7gMfx1vFxw@mail.gmail.com>
 <CAA48SF_8fpq9UFdTHO0x_ECqLhJnRkKi6kBrUMCyeJ7yOmpVRA@mail.gmail.com>
 <CANY7k6=CRaUX+SV6T0MfPtxa5k+VddXcbu9kYRZLFdhrkwgMqw@mail.gmail.com>
Message-ID: <CAA48SF-husC12wY-fpyTrGVSW4tNJAQ-MHe-5g2q-+J3Q1YgyA@mail.gmail.com>

Please don't drop the mailing list from the replies.

Ah, I ran it by invoking the script in an IPython session where `plt.ion()`
has been called and `plt.show()` in non-blocking.  If I run it as as script
I see what you descirbe!

Removing the `plt.show()` calls from inside of the re-draw function allows
it to run end-to-end and write out the animation.

Tom

On Sun, May 19, 2019 at 5:59 PM Erdem <farukerdemoncel at gmail.com> wrote:

> Thank you very much.
>
> My operating system is Ubuntu 18.04 LTS 64 bit. I've set up a virtual
> python environment and to activate I use this command.
>
> $ . venv/bin/activate
>
> I've saved source file as convolution py. To run the source code I use
> this command
>
> $ python convolution.py
>
> But rather than an animation I see only a plot of integral at t0=-2.00
>
> [image: convolution.png]
>
> I wait some time and nothing happens. I've also tried to close window a
> few times and the result is same.
>
> Since you may be able to get an mp4 file of the animation may it be
> because of some codecs are missing or may be a bug?
>
> Erdem
>
> Thomas Caswell <tcaswell at gmail.com>, 20 May 2019 Pzt, 00:17 tarihinde
> ?unu yazd?:
>
>> Erdem,
>>
>> I do not understand your question.  If I run that code I do get an mp4
>> file of the animation.
>>
>> Tom
>>
>>
>> On Sat, May 18, 2019 at 6:05 PM Erdem <farukerdemoncel at gmail.com> wrote:
>>
>>> This example is taken from a tutorial
>>> <https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html> related
>>> to convolution integral.
>>>
>>> I would like to export this example as animation in mp4 format. So far,
>>> the code looks like this :
>>>
>>> import scipy.integrateimport numpy as npimport matplotlib.pyplot as pltimport matplotlib.animation as animation
>>> def showConvolution(t0,f1, f2):
>>>     # Calculate the overall convolution result using Simpson integration
>>>     convolution = np.zeros(len(t))
>>>     for n, t_ in enumerate(t):
>>>         prod = lambda tau: f1(tau) * f2(t_-tau)
>>>         convolution[n] = scipy.integrate.simps(prod(t), t)
>>>
>>>     # Create the shifted and flipped function
>>>     f_shift = lambda t: f2(t0-t)
>>>     prod = lambda tau: f1(tau) * f2(t0-tau)
>>>
>>>     # Plot the curves
>>>     plt.gcf().clear() # il
>>>
>>>     plt.subplot(211)
>>>     plt.gca().set_ymargin(0.05) # il
>>>     plt.plot(t, f1(t), label=r'$f_1(\tau)$')
>>>     plt.plot(t, f_shift(t), label=r'$f_2(t_0-\tau)$')
>>>     plt.fill(t, prod(t), color='r', alpha=0.5, edgecolor='black', hatch='//') # il
>>>     plt.plot(t, prod(t), 'r-', label=r'$f_1(\tau)f_2(t_0-\tau)$')
>>>     plt.grid(True); plt.xlabel(r'$\tau$'); plt.ylabel(r'$x(\tau)$') # il
>>>     plt.legend(fontsize=10) # il
>>>     plt.text(-4, 0.6, '$t_0=%.2f$' % t0, bbox=dict(fc='white')) # il
>>>
>>>     # plot the convolution curve
>>>     plt.subplot(212)
>>>     plt.gca().set_ymargin(0.05) # il
>>>     plt.plot(t, convolution, label='$(f_1*f_2)(t)$')
>>>
>>>     # recalculate the value of the convolution integral at the current time-shift t0
>>>     current_value = scipy.integrate.simps(prod(t), t)
>>>     plt.plot(t0, current_value, 'ro')  # plot the point
>>>     plt.grid(True); plt.xlabel('$t$'); plt.ylabel('$(f_1*f_2)(t)$') # il
>>>     plt.legend(fontsize=10) # il
>>>     plt.show() # il
>>> Fs = 50  # our sampling frequency for the plotting
>>> T = 5    # the time range we are interested in
>>> t = np.arange(-T, T, 1/Fs)  # the time samples
>>> f1 = lambda t: np.maximum(0, 1-abs(t))
>>> f2 = lambda t: (t>0) * np.exp(-2*t)
>>>
>>> t0 = np.arange(-2.0,2.0, 0.05)
>>>
>>> fig = plt.figure(figsize=(8,3))
>>> anim = animation.FuncAnimation(fig, showConvolution, frames=t0, fargs=(f1,f2),interval=80)
>>>
>>> anim.save('animation.mp4', fps=30) # fps = frames per second
>>>
>>> plt.show()
>>>
>>>
>>> When I run the program I see the output of see the output of convolution
>>> integral at t0 = -0.20.
>>>
>>> [image: convolution.png]
>>>
>>> Is there a way to change t0 so that I'd like to able to save it as
>>> animation as in the tutorial
>>> <https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html> In
>>> the example t0 decreases from -2.0 to -1.95 etc the green curve is shifted
>>> right, and the area between curves, product increases. In the tutorial
>>> there is an html animation and I would like to save as mp4 file.
>>>
>>> I've also added source code as an attachment.
>>> _______________________________________________
>>> Matplotlib-users mailing list
>>> Matplotlib-users at python.org
>>> https://mail.python.org/mailman/listinfo/matplotlib-users
>>>
>>
>>
>> --
>> Thomas Caswell
>> tcaswell at gmail.com
>>
>

-- 
Thomas Caswell
tcaswell at gmail.com
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From tcaswell at gmail.com  Sun May 19 18:24:30 2019
From: tcaswell at gmail.com (Thomas Caswell)
Date: Sun, 19 May 2019 18:24:30 -0400
Subject: [Matplotlib-users] Convolution integral export as animation
In-Reply-To: <CANY7k6=-epWUweBKkz7acnbyDFCr7WA6Qhb64LQUny15rfi1cQ@mail.gmail.com>
References: <CANY7k6n2m03UB1=UOjO8Z30Eja-zd9w9mJQNgWrA7gMfx1vFxw@mail.gmail.com>
 <CAA48SF_8fpq9UFdTHO0x_ECqLhJnRkKi6kBrUMCyeJ7yOmpVRA@mail.gmail.com>
 <CANY7k6=CRaUX+SV6T0MfPtxa5k+VddXcbu9kYRZLFdhrkwgMqw@mail.gmail.com>
 <CAA48SF-husC12wY-fpyTrGVSW4tNJAQ-MHe-5g2q-+J3Q1YgyA@mail.gmail.com>
 <CANY7k6=-epWUweBKkz7acnbyDFCr7WA6Qhb64LQUny15rfi1cQ@mail.gmail.com>
Message-ID: <CAA48SF-FonTukTR7-28fw1wLUHZuH29-1UKX7fOf+6fSEj83tg@mail.gmail.com>

Try 'reply-all' instead?

Yes, that is controlled by the fps kwarg to `anim.save`.

Glad it is working!

Tom

On Sun, May 19, 2019 at 6:23 PM Erdem <farukerdemoncel at gmail.com> wrote:

> My reply does not show in the mail list. I have no idea why this happened
> but I simply use Gmail to reply. I used to use Gnus message reader with
> Emacs but I think it is not installed for now.
>
> Thanks now it works as expected!
>
> Is there a way to slow down animation a bit.
>
> Erdem
>
>
> Thomas Caswell <tcaswell at gmail.com>, 20 May 2019 Pzt, 01:05 tarihinde
> ?unu yazd?:
>
>> Please don't drop the mailing list from the replies.
>>
>> Ah, I ran it by invoking the script in an IPython session where
>> `plt.ion()` has been called and `plt.show()` in non-blocking.  If I run it
>> as as script I see what you descirbe!
>>
>> Removing the `plt.show()` calls from inside of the re-draw function
>> allows it to run end-to-end and write out the animation.
>>
>> Tom
>>
>> On Sun, May 19, 2019 at 5:59 PM Erdem <farukerdemoncel at gmail.com> wrote:
>>
>>> Thank you very much.
>>>
>>> My operating system is Ubuntu 18.04 LTS 64 bit. I've set up a virtual
>>> python environment and to activate I use this command.
>>>
>>> $ . venv/bin/activate
>>>
>>> I've saved source file as convolution py. To run the source code I use
>>> this command
>>>
>>> $ python convolution.py
>>>
>>> But rather than an animation I see only a plot of integral at t0=-2.00
>>>
>>> [image: convolution.png]
>>>
>>> I wait some time and nothing happens. I've also tried to close window a
>>> few times and the result is same.
>>>
>>> Since you may be able to get an mp4 file of the animation may it be
>>> because of some codecs are missing or may be a bug?
>>>
>>> Erdem
>>>
>>> Thomas Caswell <tcaswell at gmail.com>, 20 May 2019 Pzt, 00:17 tarihinde
>>> ?unu yazd?:
>>>
>>>> Erdem,
>>>>
>>>> I do not understand your question.  If I run that code I do get an mp4
>>>> file of the animation.
>>>>
>>>> Tom
>>>>
>>>>
>>>> On Sat, May 18, 2019 at 6:05 PM Erdem <farukerdemoncel at gmail.com>
>>>> wrote:
>>>>
>>>>> This example is taken from a tutorial
>>>>> <https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html> related
>>>>> to convolution integral.
>>>>>
>>>>> I would like to export this example as animation in mp4 format. So
>>>>> far, the code looks like this :
>>>>>
>>>>> import scipy.integrateimport numpy as npimport matplotlib.pyplot as pltimport matplotlib.animation as animation
>>>>> def showConvolution(t0,f1, f2):
>>>>>     # Calculate the overall convolution result using Simpson integration
>>>>>     convolution = np.zeros(len(t))
>>>>>     for n, t_ in enumerate(t):
>>>>>         prod = lambda tau: f1(tau) * f2(t_-tau)
>>>>>         convolution[n] = scipy.integrate.simps(prod(t), t)
>>>>>
>>>>>     # Create the shifted and flipped function
>>>>>     f_shift = lambda t: f2(t0-t)
>>>>>     prod = lambda tau: f1(tau) * f2(t0-tau)
>>>>>
>>>>>     # Plot the curves
>>>>>     plt.gcf().clear() # il
>>>>>
>>>>>     plt.subplot(211)
>>>>>     plt.gca().set_ymargin(0.05) # il
>>>>>     plt.plot(t, f1(t), label=r'$f_1(\tau)$')
>>>>>     plt.plot(t, f_shift(t), label=r'$f_2(t_0-\tau)$')
>>>>>     plt.fill(t, prod(t), color='r', alpha=0.5, edgecolor='black', hatch='//') # il
>>>>>     plt.plot(t, prod(t), 'r-', label=r'$f_1(\tau)f_2(t_0-\tau)$')
>>>>>     plt.grid(True); plt.xlabel(r'$\tau$'); plt.ylabel(r'$x(\tau)$') # il
>>>>>     plt.legend(fontsize=10) # il
>>>>>     plt.text(-4, 0.6, '$t_0=%.2f$' % t0, bbox=dict(fc='white')) # il
>>>>>
>>>>>     # plot the convolution curve
>>>>>     plt.subplot(212)
>>>>>     plt.gca().set_ymargin(0.05) # il
>>>>>     plt.plot(t, convolution, label='$(f_1*f_2)(t)$')
>>>>>
>>>>>     # recalculate the value of the convolution integral at the current time-shift t0
>>>>>     current_value = scipy.integrate.simps(prod(t), t)
>>>>>     plt.plot(t0, current_value, 'ro')  # plot the point
>>>>>     plt.grid(True); plt.xlabel('$t$'); plt.ylabel('$(f_1*f_2)(t)$') # il
>>>>>     plt.legend(fontsize=10) # il
>>>>>     plt.show() # il
>>>>> Fs = 50  # our sampling frequency for the plotting
>>>>> T = 5    # the time range we are interested in
>>>>> t = np.arange(-T, T, 1/Fs)  # the time samples
>>>>> f1 = lambda t: np.maximum(0, 1-abs(t))
>>>>> f2 = lambda t: (t>0) * np.exp(-2*t)
>>>>>
>>>>> t0 = np.arange(-2.0,2.0, 0.05)
>>>>>
>>>>> fig = plt.figure(figsize=(8,3))
>>>>> anim = animation.FuncAnimation(fig, showConvolution, frames=t0, fargs=(f1,f2),interval=80)
>>>>>
>>>>> anim.save('animation.mp4', fps=30) # fps = frames per second
>>>>>
>>>>> plt.show()
>>>>>
>>>>>
>>>>> When I run the program I see the output of see the output of
>>>>> convolution integral at t0 = -0.20.
>>>>>
>>>>> [image: convolution.png]
>>>>>
>>>>> Is there a way to change t0 so that I'd like to able to save it as
>>>>> animation as in the tutorial
>>>>> <https://dspillustrations.com/pages/posts/misc/convolution-examples-and-the-convolution-integral.html> In
>>>>> the example t0 decreases from -2.0 to -1.95 etc the green curve is shifted
>>>>> right, and the area between curves, product increases. In the tutorial
>>>>> there is an html animation and I would like to save as mp4 file.
>>>>>
>>>>> I've also added source code as an attachment.
>>>>> _______________________________________________
>>>>> Matplotlib-users mailing list
>>>>> Matplotlib-users at python.org
>>>>> https://mail.python.org/mailman/listinfo/matplotlib-users
>>>>>
>>>>
>>>>
>>>> --
>>>> Thomas Caswell
>>>> tcaswell at gmail.com
>>>>
>>>
>>
>> --
>> Thomas Caswell
>> tcaswell at gmail.com
>>
>

-- 
Thomas Caswell
tcaswell at gmail.com
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From tcaswell at gmail.com  Sun May 19 18:54:45 2019
From: tcaswell at gmail.com (Thomas Caswell)
Date: Sun, 19 May 2019 18:54:45 -0400
Subject: [Matplotlib-users] Matplotlib plots display as blank in
 interactive mode with no error messages - (one) Solution
In-Reply-To: <1558252250113-0.post@n5.nabble.com>
References: <1558084766050-0.post@n5.nabble.com>
 <CAA48SF8u8_7ibhjito5d-9WmdtPyP8aWiiZVJWU7=h84ZOYTkw@mail.gmail.com>
 <1558252250113-0.post@n5.nabble.com>
Message-ID: <CAA48SF-U-6NqmWO7m9M6W7WSqvJPvHUkUGEqOD1YRVg6Of_XuA@mail.gmail.com>

Indeed, sorry for the misdirection.

If you look in your terminal do you see a bunch of tracebacks?

The problem is that Python read \0 in a string literal as an escaped 0 byte
(aka \x00) which fails to parse with with mathtex and latex.  If you make a
raw string (r"$\0$") python won't interpret the escape character, but both
mathtex and latex still fail as \0 is not a valid command it latex.  These
exceptions are being raised as part of the draw process which cause it to
fail which makes it look like interactivity is lost because the updated
image is not shipped to the browser.

We should sort out a better way to surface those exceptions, the problem is
that they happen asynchronously so it is not clear where they should be
raised...

Tom

On Sun, May 19, 2019 at 3:51 AM FilipPersson <filip at ownit.nu> wrote:

> Hi Tom,
> I'm not sure if it's related. I'm using nbAgg. It acme automatically when I
> installed and I haven't changed it. Their plots go black. Not all my plots
> go crazy when I do the escape character error, only the interactive ones
> when re-running.
>
>
>
> --
> Sent from:
> http://matplotlib.1069221.n5.nabble.com/matplotlib-users-f3.html
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users
>


-- 
Thomas Caswell
tcaswell at gmail.com
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From heiland at iu.edu  Tue May 21 11:42:26 2019
From: heiland at iu.edu (Heiland, Randy)
Date: Tue, 21 May 2019 15:42:26 +0000
Subject: [Matplotlib-users] scatter plot with data coord sized glyphs
Message-ID: <690CAFBA-17E4-49AE-913C-78EC7169F747@iu.edu>

Hello,

Is it possible to specify scatter plot glyph sizes - specifically, circles and, e.g., radii, in data coords, rather than ?marker size? of ?points**2??

thanks, Randy
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From selasley at icloud.com  Tue May 21 12:35:29 2019
From: selasley at icloud.com (Scott Lasley)
Date: Tue, 21 May 2019 12:35:29 -0400
Subject: [Matplotlib-users] scatter plot with data coord sized glyphs
In-Reply-To: <690CAFBA-17E4-49AE-913C-78EC7169F747@iu.edu>
References: <690CAFBA-17E4-49AE-913C-78EC7169F747@iu.edu>
Message-ID: <1B9962D3-8260-4EB3-AB3A-0F065977EEA5@icloud.com>

Syrtis Major's gist at  https://gist.github.com/syrte/592a062c562cd2a98a83  seems to do what you want.  See this stackoverflow answer for an example of the circles function in action - 
https://stackoverflow.com/questions/9081553/python-scatter-plot-size-and-style-of-the-marker/24567352#24567352

hth,
Scott

> On May 21, 2019, at 11:42 AM, Heiland, Randy <heiland at iu.edu> wrote:
> 
> Hello,
> Is it possible to specify scatter plot glyph sizes - specifically, circles and, e.g., radii, in data coords, rather than ?marker size? of ?points**2??
> thanks, Randy

From heiland at iu.edu  Tue May 21 14:08:32 2019
From: heiland at iu.edu (Heiland, Randy)
Date: Tue, 21 May 2019 18:08:32 +0000
Subject: [Matplotlib-users] scatter plot with data coord sized glyphs
In-Reply-To: <1B9962D3-8260-4EB3-AB3A-0F065977EEA5@icloud.com>
References: <690CAFBA-17E4-49AE-913C-78EC7169F747@iu.edu>
 <1B9962D3-8260-4EB3-AB3A-0F065977EEA5@icloud.com>
Message-ID: <A8F1ACEF-410A-4F51-9E18-FC39929B3A3D@iu.edu>

Thanks Scott! That certainly gets me closer. One question/problem I still have is that it doesn?t seem to like RGB as colors, in spite of the docs. I?ve attached a simple  example.

Randy

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> On May 21, 2019, at 12:35 PM, Scott Lasley <selasley at icloud.com> wrote:
> 
> Syrtis Major's gist at  https://gist.github.com/syrte/592a062c562cd2a98a83  seems to do what you want.  See this stackoverflow answer for an example of the circles function in action - 
> https://stackoverflow.com/questions/9081553/python-scatter-plot-size-and-style-of-the-marker/24567352#24567352
> 
> hth,
> Scott
> 
>> On May 21, 2019, at 11:42 AM, Heiland, Randy <heiland at iu.edu> wrote:
>> 
>> Hello,
>> Is it possible to specify scatter plot glyph sizes - specifically, circles and, e.g., radii, in data coords, rather than ?marker size? of ?points**2??
>> thanks, Randy

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From selasley at icloud.com  Tue May 21 14:39:28 2019
From: selasley at icloud.com (Scott Lasley)
Date: Tue, 21 May 2019 14:39:28 -0400
Subject: [Matplotlib-users] scatter plot with data coord sized glyphs
In-Reply-To: <A8F1ACEF-410A-4F51-9E18-FC39929B3A3D@iu.edu>
References: <690CAFBA-17E4-49AE-913C-78EC7169F747@iu.edu>
 <1B9962D3-8260-4EB3-AB3A-0F065977EEA5@icloud.com>
 <A8F1ACEF-410A-4F51-9E18-FC39929B3A3D@iu.edu>
Message-ID: <61CE5312-0DF1-491E-80EA-4FB44ECB9642@icloud.com>

From the docstring in circles - "Note that `c` should not be a single numeric RGB or RGBA sequence because that is indistinguishable from an array of values to be colormapped. (If you insist, use `color` instead).   So a slight modification of your code seems to do what you want


fig = plt.figure(figsize=(5,3))
ax = fig.gca()
ax.set_aspect("equal")

xvals = np.array([0,100])
yvals = np.array([0,0])
rvals = np.array([30,10])

rgb = np.array([[255, 0, 0], [0, 255, 0]])

circles(xvals, yvals, s=rvals, color=rgb / 255.)  # use color instead of c and make  0. <= rgb <= 1.

plt.xlim(-30,110)
plt.ylim(-30,30)
plt.show()

Scott


> On May 21, 2019, at 2:08 PM, Heiland, Randy <heiland at iu.edu> wrote:
> 
> Thanks Scott! That certainly gets me closer. One question/problem I still have is that it doesn?t seem to like RGB as colors, in spite of the docs. I?ve attached a simple  example.
> 
> Randy
> 
> <test_circ2.py>
> 
>> On May 21, 2019, at 12:35 PM, Scott Lasley <selasley at icloud.com> wrote:
>> 
>> Syrtis Major's gist at  https://gist.github.com/syrte/592a062c562cd2a98a83  seems to do what you want.  See this stackoverflow answer for an example of the circles function in action - 
>> https://stackoverflow.com/questions/9081553/python-scatter-plot-size-and-style-of-the-marker/24567352#24567352
>> 
>> hth,
>> Scott
>> 
>>> On May 21, 2019, at 11:42 AM, Heiland, Randy <heiland at iu.edu> wrote:
>>> 
>>> Hello,
>>> Is it possible to specify scatter plot glyph sizes - specifically, circles and, e.g., radii, in data coords, rather than ?marker size? of ?points**2??
>>> thanks, Randy
> 


From heiland at iu.edu  Wed May 22 07:15:55 2019
From: heiland at iu.edu (Heiland, Randy)
Date: Wed, 22 May 2019 11:15:55 +0000
Subject: [Matplotlib-users] scatter plot with data coord sized glyphs
In-Reply-To: <61CE5312-0DF1-491E-80EA-4FB44ECB9642@icloud.com>
References: <690CAFBA-17E4-49AE-913C-78EC7169F747@iu.edu>
 <1B9962D3-8260-4EB3-AB3A-0F065977EEA5@icloud.com>
 <A8F1ACEF-410A-4F51-9E18-FC39929B3A3D@iu.edu>
 <61CE5312-0DF1-491E-80EA-4FB44ECB9642@icloud.com>
Message-ID: <4CF15809-8DF6-4311-83F1-760BCADA823A@iu.edu>

Scott, thanks for the help once again! Yes, the results are exactly what I want, and seem to be quite fast for lots of circles.

Randy

> On May 21, 2019, at 2:39 PM, Scott Lasley <selasley at icloud.com> wrote:
> 
> From the docstring in circles - "Note that `c` should not be a single numeric RGB or RGBA sequence because that is indistinguishable from an array of values to be colormapped. (If you insist, use `color` instead).   So a slight modification of your code seems to do what you want
> 
> 
> fig = plt.figure(figsize=(5,3))
> ax = fig.gca()
> ax.set_aspect("equal")
> 
> xvals = np.array([0,100])
> yvals = np.array([0,0])
> rvals = np.array([30,10])
> 
> rgb = np.array([[255, 0, 0], [0, 255, 0]])
> 
> circles(xvals, yvals, s=rvals, color=rgb / 255.)  # use color instead of c and make  0. <= rgb <= 1.
> 
> plt.xlim(-30,110)
> plt.ylim(-30,30)
> plt.show()
> 
> Scott
> 
> 
>> On May 21, 2019, at 2:08 PM, Heiland, Randy <heiland at iu.edu> wrote:
>> 
>> Thanks Scott! That certainly gets me closer. One question/problem I still have is that it doesn?t seem to like RGB as colors, in spite of the docs. I?ve attached a simple  example.
>> 
>> Randy
>> 
>> <test_circ2.py>
>> 
>>> On May 21, 2019, at 12:35 PM, Scott Lasley <selasley at icloud.com> wrote:
>>> 
>>> Syrtis Major's gist at  https://gist.github.com/syrte/592a062c562cd2a98a83  seems to do what you want.  See this stackoverflow answer for an example of the circles function in action - 
>>> https://stackoverflow.com/questions/9081553/python-scatter-plot-size-and-style-of-the-marker/24567352#24567352
>>> 
>>> hth,
>>> Scott
>>> 
>>>> On May 21, 2019, at 11:42 AM, Heiland, Randy <heiland at iu.edu> wrote:
>>>> 
>>>> Hello,
>>>> Is it possible to specify scatter plot glyph sizes - specifically, circles and, e.g., radii, in data coords, rather than ?marker size? of ?points**2??
>>>> thanks, Randy
>> 
> 

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From bruno.pagani at astrophysics.eu  Wed May 22 14:40:07 2019
From: bruno.pagani at astrophysics.eu (Bruno Pagani)
Date: Wed, 22 May 2019 20:40:07 +0200
Subject: [Matplotlib-users] Get color from legend for errorbar plots
In-Reply-To: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>
References: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>
Message-ID: <bc942233-228b-1b4d-6f4c-f4f32abfe0ab@astrophysics.eu>

Le 22/05/2019 ? 20:34, Bruno Pagani a ?crit?:
> Hi,
>
> I?ve stumbled upon this very exact issue, for which there is no posted
> answer:
> https://stackoverflow.com/questions/26573864/matplotlib-get-errorbar-color-from-legend
>
> Does anyone have an idea?
>
> Regards,
> Bruno

As a side note, I have a workaround that rely on issuing a subsequent
plt.plot with the same data without errorbars, but if someone has a
better solution?


From bruno.pagani at astrophysics.eu  Wed May 22 14:34:14 2019
From: bruno.pagani at astrophysics.eu (Bruno Pagani)
Date: Wed, 22 May 2019 20:34:14 +0200
Subject: [Matplotlib-users] Get color from legend for errorbar plots
Message-ID: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>

Hi,

I?ve stumbled upon this very exact issue, for which there is no posted
answer:
https://stackoverflow.com/questions/26573864/matplotlib-get-errorbar-color-from-legend

Does anyone have an idea?

Regards,
Bruno


From selasley at icloud.com  Wed May 22 17:43:17 2019
From: selasley at icloud.com (Scott Lasley)
Date: Wed, 22 May 2019 17:43:17 -0400
Subject: [Matplotlib-users] Get color from legend for errorbar plots
In-Reply-To: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>
References: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>
Message-ID: <D31B30D1-4C18-486C-987C-FD09D04F2A2D@icloud.com>

As Tom Caswell pointed out, you can use the legendHandles.  Something like this may do what you want

plt.errorbar([1,2,3],[1,2,3],yerr=0.2,label='22')
plt.errorbar([3,1,2],[2,3,1],yerr=0.3,label='33')
z  = plt.legend()
[lc.get_colors() for lc in z.legendHandles]

hth,
Scott

> On May 22, 2019, at 2:34 PM, Bruno Pagani <bruno.pagani at astrophysics.eu> wrote:
> 
> Hi,
> I?ve stumbled upon this very exact issue, for which there is no posted
> answer:
> https://stackoverflow.com/questions/26573864/matplotlib-get-errorbar-color-from-legend
> Does anyone have an idea?
> Regards,
> Bruno

From bruno.pagani at astrophysics.eu  Thu May 23 06:34:25 2019
From: bruno.pagani at astrophysics.eu (Bruno Pagani)
Date: Thu, 23 May 2019 12:34:25 +0200
Subject: [Matplotlib-users] Get color from legend for errorbar plots
In-Reply-To: <D31B30D1-4C18-486C-987C-FD09D04F2A2D@icloud.com>
References: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>
 <D31B30D1-4C18-486C-987C-FD09D04F2A2D@icloud.com>
Message-ID: <a417075f-727b-9143-7355-fea2eee01821@astrophysics.eu>

Le 22/05/2019 ? 23:43, Scott Lasley a ?crit?:
> As Tom Caswell pointed out, you can use the legendHandles.  Something like this may do what you want
>
> plt.errorbar([1,2,3],[1,2,3],yerr=0.2,label='22')
> plt.errorbar([3,1,2],[2,3,1],yerr=0.3,label='33')
> z  = plt.legend()
> [lc.get_colors() for lc in z.legendHandles]
>
> hth,
> Scott

Note that for some reason lc.get_colors() returns array of color in rgba
format, e.g. [[r g b a]]. So I had to do lc.get_colors()[0] instead, but
then it works fine.

Thanks for your help,
Bruno


From pmhobson at gmail.com  Thu May 23 09:28:20 2019
From: pmhobson at gmail.com (Paul Hobson)
Date: Thu, 23 May 2019 06:28:20 -0700
Subject: [Matplotlib-users] Get color from legend for errorbar plots
In-Reply-To: <a417075f-727b-9143-7355-fea2eee01821@astrophysics.eu>
References: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>
 <D31B30D1-4C18-486C-987C-FD09D04F2A2D@icloud.com>
 <a417075f-727b-9143-7355-fea2eee01821@astrophysics.eu>
Message-ID: <CADT3MEA5Q2odw9C5fTqfEuNB71CW7RSNv2LwvYB3iQao7sHJ5g@mail.gmail.com>

Hey Bruno,

In this case, I believe `lc` is a LineCollection, so it's essentially a
sequence of N lines. In this case, it appear N = 1.
-p

On Thu, May 23, 2019 at 3:34 AM Bruno Pagani <bruno.pagani at astrophysics.eu>
wrote:

> Le 22/05/2019 ? 23:43, Scott Lasley a ?crit :
> > As Tom Caswell pointed out, you can use the legendHandles.  Something
> like this may do what you want
> >
> > plt.errorbar([1,2,3],[1,2,3],yerr=0.2,label='22')
> > plt.errorbar([3,1,2],[2,3,1],yerr=0.3,label='33')
> > z  = plt.legend()
> > [lc.get_colors() for lc in z.legendHandles]
> >
> > hth,
> > Scott
>
> Note that for some reason lc.get_colors() returns array of color in rgba
> format, e.g. [[r g b a]]. So I had to do lc.get_colors()[0] instead, but
> then it works fine.
>
> Thanks for your help,
> Bruno
>
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users
>
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From bruno.pagani at astrophysics.eu  Thu May 23 09:32:44 2019
From: bruno.pagani at astrophysics.eu (Bruno Pagani)
Date: Thu, 23 May 2019 15:32:44 +0200
Subject: [Matplotlib-users] Get color from legend for errorbar plots
In-Reply-To: <CADT3MEA5Q2odw9C5fTqfEuNB71CW7RSNv2LwvYB3iQao7sHJ5g@mail.gmail.com>
References: <096092ec-2b07-d2dd-defb-ac575ad0c3a0@astrophysics.eu>
 <D31B30D1-4C18-486C-987C-FD09D04F2A2D@icloud.com>
 <a417075f-727b-9143-7355-fea2eee01821@astrophysics.eu>
 <CADT3MEA5Q2odw9C5fTqfEuNB71CW7RSNv2LwvYB3iQao7sHJ5g@mail.gmail.com>
Message-ID: <2cdd4725-e123-0bf3-5001-dab0efd43483@astrophysics.eu>

Le 23/05/2019 ? 15:28, Paul Hobson a ?crit?:
> Hey Bruno,
>
> In this case, I believe `lc` is a LineCollection, so it's essentially
> a sequence of N lines. In this case, it appear N = 1.
> -p

Makes sense, thx.

I?m posting an answer to the stackexchange question crediting all of you
for your pointers.

Regards,
Bruno


From tcaswell at gmail.com  Sat May 25 21:11:22 2019
From: tcaswell at gmail.com (Thomas Caswell)
Date: Sat, 25 May 2019 21:11:22 -0400
Subject: [Matplotlib-users] Autoscaling Date Locator with minor ticks?
In-Reply-To: <20190504010908.GA9339@shallowsky.com>
References: <20190504010908.GA9339@shallowsky.com>
Message-ID: <CAA48SF_USoVVPo0u5Zv_v0YbGn8AW0i9wo4-XXv3jm1v=30bLg@mail.gmail.com>

Akanna,

Setting the minor and major locators in the correct approach, but you need
to set them with different settings (as other wise they will decide to put
the ticks at the sameplaces, hence the "doubled" labels. This behavior
changed with 3.1 (see
https://matplotlib.org/api/api_changes.html#major-minor-tick-collisions )
and going forward the overlapping minor ticks will be trimmed by default).
I suspect that by playing with `minticks` and `maxticks` you can get the
effect you want:


import numpy as np
import matplotlib.dates as mdates
import matplotlib.pyplot as plt

t = np.arange("2018-11-03", "2018-11-06", dtype="datetime64")
x = np.random.rand(len(t))

fig, ax = plt.subplots()
ax.plot(t, x)
ax.xaxis.set(
    major_locator=mdates.AutoDateLocator(minticks=1, maxticks=5),
    minor_locator=mdates.AutoDateLocator(minticks=15, maxticks=52),
)

plt.show()


You may also be interested in the ConciseDateFormatter (
https://matplotlib.org/users/whats_new.html#concisedateformatter ) that is
new in 3.1.

Tom

On Fri, May 3, 2019 at 9:16 PM Akkana Peck <akkana at shallowsky.com> wrote:

> Is there any way to get AutoDateLocator to handle minor ticks as
> well as major ones?
>
> For instance, if I have a plot spanning a few days, I'd like to be
> able to show the date as a label and major tick, but show minor
> ticks for hours, or one minor tick every six hours, whatever is
> sensible depending on the scale. Or on a plot spanning a few years,
> show labels for each year, but with 12 minor ticks showing months.
> It seems like AutoDateLocator only draws major ticks.
>
> I can write a custom date locator that handles the minor ticks
> nicely, but then I don't get the nice auto-scaling of
> AutoDateLocator, and if I plot a larger or smaller date range,
> my labels and ticks become too crowded or too sparse.
>
> I tried setting both major and minor locators to AutoDateLocators:
>     ax.xaxis.set_major_locator(AutoDateLocator())
>     ax.xaxis.set_minor_locator(AutoDateLocator())
> and similarly with set_*_formatter(), but that just gave me
> smeary-looking double-printed major labels and ticks.
>
> Maybe I need to write a custom smart locator that reproduces
> AutoDateLocator's auto-scaling while also handling ticks. But before
> I dive into that, I thought I'd ask; I can't be the only person who
> needs more precise ticks and labeling than AutoDateLocator provides.
>
> Thanks!
>
>         ...Akkana
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users
>


-- 
Thomas Caswell
tcaswell at gmail.com
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From pnsinha68 at gmail.com  Fri May 31 05:07:26 2019
From: pnsinha68 at gmail.com (Partha Sinha)
Date: Fri, 31 May 2019 14:37:26 +0530
Subject: [Matplotlib-users] plot
Message-ID: <CADcgpJekCQonreOfdbDhi3jU65u=1526Xpdhm506TmgG0k3Kqw@mail.gmail.com>

I want help on graph
I need to plot numbers one by one (lets say after interval of 5 sec) but
all in the same graph. How to do ?
My code is below


import time
import matplotlib.pyplot as plt
import numpy as np
from random import randint
i = 1
numbers = [0]*5
while i < 5:
     numbers[i] = randint(0,100)
     plt.plot(np.arange(1,6),numbers, 'o')
     i += 1
     matplotlib.pyplot.draw()
     time.sleep(5)
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From selasley at icloud.com  Fri May 31 11:40:53 2019
From: selasley at icloud.com (Scott Lasley)
Date: Fri, 31 May 2019 11:40:53 -0400
Subject: [Matplotlib-users] plot
In-Reply-To: <CADcgpJekCQonreOfdbDhi3jU65u=1526Xpdhm506TmgG0k3Kqw@mail.gmail.com>
References: <CADcgpJekCQonreOfdbDhi3jU65u=1526Xpdhm506TmgG0k3Kqw@mail.gmail.com>
Message-ID: <4295DD0C-4014-4C0D-B3CE-CFCD1D331D48@icloud.com>

Try using plt.pause instead of time.sleep.  This may do what you want

import matplotlib.pyplot as plt
from random import randint

numbers = [0]*5
# draw the initial points
oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
plt.pause(5)
for i in range(5):
    numbers[i] = randint(0,100)
    # remove the previously plotted lines before drawing the new ones
    oldlines[0].remove()
    oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
    plt.pause(5)



> On May 31, 2019, at 5:07 AM, Partha Sinha <pnsinha68 at gmail.com> wrote:
> 
> I want help on graph
> I need to plot numbers one by one (lets say after interval of 5 sec) but all in the same graph. How to do ?
> My code is below
> 
> 
> import time    
> import matplotlib.pyplot as plt
> import numpy as np
> from random import randint
> i = 1
> numbers = [0]*5
> while i < 5:
>      numbers[i] = randint(0,100)
>      plt.plot(np.arange(1,6),numbers, 'o')
>      i += 1
>      matplotlib.pyplot.draw()
>      time.sleep(5)
> _______________________________________________
> Matplotlib-users mailing list
> Matplotlib-users at python.org
> https://mail.python.org/mailman/listinfo/matplotlib-users


From pnsinha68 at gmail.com  Fri May 31 12:11:27 2019
From: pnsinha68 at gmail.com (Partha Sinha)
Date: Fri, 31 May 2019 21:41:27 +0530
Subject: [Matplotlib-users] plot
In-Reply-To: <4295DD0C-4014-4C0D-B3CE-CFCD1D331D48@icloud.com>
References: <CADcgpJekCQonreOfdbDhi3jU65u=1526Xpdhm506TmgG0k3Kqw@mail.gmail.com>
 <4295DD0C-4014-4C0D-B3CE-CFCD1D331D48@icloud.com>
Message-ID: <CADcgpJdo1n180A9GzyA8wcyLVm3=zidtdVUspPuF0sGT_bnm-A@mail.gmail.com>

It worked. However, I was looking for in one graph but here it's producing
n no of graphs. can we make it in the graph ?
partha


On Fri, 31 May 2019 at 21:10, Scott Lasley <selasley at icloud.com> wrote:

> Try using plt.pause instead of time.sleep.  This may do what you want
>
> import matplotlib.pyplot as plt
> from random import randint
>
> numbers = [0]*5
> # draw the initial points
> oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
> plt.pause(5)
> for i in range(5):
>     numbers[i] = randint(0,100)
>     # remove the previously plotted lines before drawing the new ones
>     oldlines[0].remove()
>     oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
>     plt.pause(5)
>
>
>
> > On May 31, 2019, at 5:07 AM, Partha Sinha <pnsinha68 at gmail.com> wrote:
> >
> > I want help on graph
> > I need to plot numbers one by one (lets say after interval of 5 sec) but
> all in the same graph. How to do ?
> > My code is below
> >
> >
> > import time
> > import matplotlib.pyplot as plt
> > import numpy as np
> > from random import randint
> > i = 1
> > numbers = [0]*5
> > while i < 5:
> >      numbers[i] = randint(0,100)
> >      plt.plot(np.arange(1,6),numbers, 'o')
> >      i += 1
> >      matplotlib.pyplot.draw()
> >      time.sleep(5)
> > _______________________________________________
> > Matplotlib-users mailing list
> > Matplotlib-users at python.org
> > https://mail.python.org/mailman/listinfo/matplotlib-users
>
>
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From selasley at icloud.com  Fri May 31 18:34:41 2019
From: selasley at icloud.com (Scott Lasley)
Date: Fri, 31 May 2019 18:34:41 -0400
Subject: [Matplotlib-users] plot
In-Reply-To: <CADcgpJdo1n180A9GzyA8wcyLVm3=zidtdVUspPuF0sGT_bnm-A@mail.gmail.com>
References: <CADcgpJekCQonreOfdbDhi3jU65u=1526Xpdhm506TmgG0k3Kqw@mail.gmail.com>
 <4295DD0C-4014-4C0D-B3CE-CFCD1D331D48@icloud.com>
 <CADcgpJdo1n180A9GzyA8wcyLVm3=zidtdVUspPuF0sGT_bnm-A@mail.gmail.com>
Message-ID: <CE14BB79-1ED1-4DFC-80AB-95BB75415C89@icloud.com>

Are you making the plots in a jupyter notebook?  The code worked for me in ipython and when saved as a file and run from the command line, but it does produce multiple plots in a jupyter notebook.  

plt.pause does not seem to work in a notebook.  The documentation for plt.pause says "This can be used for crude animation. For more complex animation, see matplotlib.animation."  The snippet below is based on the matplotlib simple animation example (https://matplotlib.org/examples/animation/basic_example.html) It works in a jupyter notebook if you use the magic
%matplotlib notebook 
or 
%matplotlib nbagg
but it does not work in jupyter lab since those magics are not supported.


%matplotlib nbagg

import numpy as np
from matplotlib import pyplot as plt
from matplotlib.animation import FuncAnimation


def draw_pts(i):
    y[i] = np.random.randint(10, 100)
    pts.set_data(x, y)
    ax.relim()
    ax.autoscale_view(scaley=True)
    return [pts]

def init_pts():
    return []

x = np.arange(1, 6)
# set y to nan's so no points are drawn initially
y = np.full(5, np.nan)

fig, ax = plt.subplots()
ax.set(xlim=[0, 6])
pts = ax.plot(x, y, 'o')[0]

anim = FuncAnimation(fig, 
                     draw_pts, 
                     frames=5, 
                     init_func=init_pts,
                     interval=2000, 
                     blit=True,
                     repeat=False)



Notes: If init_func is not set, draw_pts is called twice with i = 0, so I used a dummy init_pts function.   ax.autoscale_view works in the jyputer notebook but the y axis does not update properly if the code is run in ipython on my mac.  If repeat=True, draw_pts will be called forever with i ranging from 0 to frames - 1 repeatedly.  interval sets the delay between updates in milliseconds.

hth,
Scott

> On May 31, 2019, at 12:11 PM, Partha Sinha <pnsinha68 at gmail.com> wrote:
> 
> It worked. However, I was looking for in one graph but here it's producing n no of graphs. can we make it in the graph ?
> partha
> 
> 
> On Fri, 31 May 2019 at 21:10, Scott Lasley <selasley at icloud.com> wrote:
> Try using plt.pause instead of time.sleep.  This may do what you want
> 
> import matplotlib.pyplot as plt
> from random import randint
> 
> numbers = [0]*5
> # draw the initial points
> oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
> plt.pause(5)
> for i in range(5):
>     numbers[i] = randint(0,100)
>     # remove the previously plotted lines before drawing the new ones
>     oldlines[0].remove()
>     oldlines = plt.plot(range(1, 6), numbers, 'o', c='r')
>     plt.pause(5)
> 
> 
> 
> > On May 31, 2019, at 5:07 AM, Partha Sinha <pnsinha68 at gmail.com> wrote:
> > 
> > I want help on graph
> > I need to plot numbers one by one (lets say after interval of 5 sec) but all in the same graph. How to do ?
> > My code is below
> > 
> > 
> > import time    
> > import matplotlib.pyplot as plt
> > import numpy as np
> > from random import randint
> > i = 1
> > numbers = [0]*5
> > while i < 5:
> >      numbers[i] = randint(0,100)
> >      plt.plot(np.arange(1,6),numbers, 'o')
> >      i += 1
> >      matplotlib.pyplot.draw()
> >      time.sleep(5)
> > _______________________________________________
> > Matplotlib-users mailing list
> > Matplotlib-users at python.org
> > https://mail.python.org/mailman/listinfo/matplotlib-users
> 


From rached.zakhama at 3-5lab.fr  Wed May 29 10:43:58 2019
From: rached.zakhama at 3-5lab.fr (Rached Zakhama)
Date: Wed, 29 May 2019 14:43:58 -0000
Subject: [Matplotlib-users] live plot
Message-ID: <28dfeee6-6e5f-b369-a770-d2e6782f4a03@3-5lab.fr>

Hi,

I was trying to make a live plot with tkinter where I can see the data 
updating live in a for loop. I used a tkinter window to plot the 
matplotlib figure and I added a button. The problem is that I can't make 
the button work during the for loop.

My example is :

##############################

# imports

import numpy as np
from time import sleep
import matplotlib
matplotlib.use("TkAgg")
from matplotlib.backends.backend_tkagg import FigureCanvasTkAgg, 
NavigationToolbar2TkAgg
from matplotlib.figure import Figure
from matplotlib.pyplot import pause
import tkinter as tk

fenetre = tk.Tk()
# update function , called whenever the user hit the button : changes 
the plot line color
def update():
 ??? n=np.random.randint(4)
 ??? colors=['b','g','r','c']
 ??? l.set_color(colors[n])
 ??? canvas.show()
# tkinter button, changes the line color
bouton = tk.Button(fenetre, text="change color", command=update)
bouton.pack()
# create random data
x=np.array([i for i in range(10)])
y=np.random.randn(10)
# create matplotlib figure and plot
fig=Figure(figsize=(5,5))
ax=fig.add_subplot(111)
l,=ax.plot(x,y)
# put the figure in the tkinter window
canvas=FigureCanvasTkAgg(fig,fenetre)
canvas.show()
canvas.get_tk_widget().pack(side=tk.TOP,fill=tk.BOTH, expand=True)
# add the toolbar
toolbar= NavigationToolbar2TkAgg(canvas,fenetre)
toolbar.update()
canvas._tkcanvas.pack(side=tk.TOP,fill=tk.BOTH, expand=True)

# update random data every? 2 seconds
for i in range(15):
 ??? sleep(2)
 ??? y=np.random.randn(10)
 ??? l.set_ydata(y)
 ??? canvas.show()


tk.mainloop()

######################

I am trying to see a plot random data changing on the screen every 2 
seconds and change its color whenever I hit the button. It doesn't work 
since apparently Python? doesn't execute the button command before 
finishing the loop.

Do you have any suggestions.

Waiting hopefully for your replay.

Best regards.

___________________________________________________________________
Rached ZAKHAMA
Bureau 2B1 33
Thales Research & Technology
III-V lab, 91120 Palaiseau,France

tel: +33(0)169416021 ?+33(0)658787715 <callto:+33%280%29169416021>
___________________________________________________________________
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From lucasmigueel at gmail.com  Wed May  1 12:19:39 2019
From: lucasmigueel at gmail.com (Lucas Carvalho)
Date: Wed, 01 May 2019 16:19:39 -0000
Subject: [Matplotlib-users] Help with 3D math drawings
Message-ID: <CA+v7Dq=k_=a4emjgk=hdSHX+dXDA9av_Ds1e=y24SorY6v0JDw@mail.gmail.com>

 Hello,

My name is Lucas and I am a technical teacher in Brazil. A group of my high
school students are using the matplotlib library to make 3D-plots but we
are having problems drawing a cutting plane into a cone, for example.

There are even other ideas, such as generating the solid resulting from the
cutting of a sphere by a plane passing through its center or in any other
position.

Would be possible to help us?

Thank you.
Regards,

-- 

Lucas Miguel de Carvalho
PhD in Bioinformatics
(UNICAMP - SP - Brazil)
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