[Matplotlib-users] Understanding axes position

[Klymak Jody]

Oops.  Just realized you can also just do

Pos =ax._postion

To get the current position.  Of course this could break because you are accessing a private variable.  

Cheers.  Jody

Sent from my iPhone

> On Sep 20, 2017, at 11:07, Jody Klymak <jklymak at uvic.ca> wrote:
> 
> Hi Nunzio,
> 
> The issue is that you call ax.set_aspect(‘equal’), and that changes the axes box. However, ax.get_position returns the frozen position, i.e. the old position. I don’t see a method to return the new position (and I wonder why get_position behaves this way).
> 
> As a work around, you can get the aspect-ratio changed position as:
> 
> figW, figH = fig.get_size_inches()
> fig_aspect = figH / figW
> newpos = pp.shrunk_to_aspect(ax.get_aspect() * ax.get_data_ratio(), pp, fig_aspect).anchored(ax.get_anchor(), pp))
> which I appreciate is a bit of a pain….
> 
> Cheers, Jody
> 
> On 20 Sep 2017, at 7:06, Nunzio Losacco wrote:
> 
> Hi all,
> 
> what I’m trying to do here is having third plot with its base aligned with the others and with reduced height (the final aim is custom positioning a colorbar).
> As you can see I’m getting the wrong position. What am I missing?
> 
> Thanks for any help
> 
> NL
> 
> # -*- coding: utf-8 -*-
> 
> from __future__ import unicode_literals
> import numpy as np
> from scipy.interpolate import griddata
> import matplotlib
> import matplotlib.pyplot as plt
> from matplotlib.patches import Circle
> from matplotlib.pylab import cm
> import matplotlib.colors as colors
> from mpl_toolkits.axes_grid1 import make_axes_locatable, axes_size
> 
> matplotlib.rcParams.update({'font.size': 8})
> 
> fig = plt.figure()
> fig.set_size_inches(6.3,6.3)
> 
> ax1 = plt.subplot(111)
> divider = make_axes_locatable(ax1)
> ax2 = divider.append_axes('right', size='100%', pad=0.3)
> 
> axes = [ax1, ax2]
> ltypes = ['dashed', 'solid']
> 
> xi = np.linspace(-18.125, 18.125, 11)
> yi = np.linspace(0, 28, 9)
> xv, yv = np.meshgrid(xi, yi)
> 
> xcOdd = 0.2
> zcOdd = 0.725
> xcEven = 0.6
> zcEven = 0.725
> 
> maskRadius = 0.15
> 
> for i in range(2):
> ax = axes[i]
> ax.set_xlabel('distance [m]')
> if i == 0:
> ax.set_ylabel('depth [m]')
> if i == 1:
> ax.set_yticklabels([])
> ax.invert_yaxis()
> ax.tick_params(direction='in')
> ax.set_aspect('equal')
> odd = Circle((xcOdd, zcOdd), .15, linewidth=1.2, color='k', fill=False)
> even = Circle((xcEven, zcEven), .15, linewidth=1.2, linestyle=ltypes[i], color='k', fill=False)
> 
> vmax = 15.
> vmin = 0.
> norm = matplotlib.colors.Normalize(vmin,vmax, clip=False)
> 
> color_map = matplotlib.colors.ListedColormap(plt.cm.Greys(np.linspace(0.25, 1, 5)), "name")
> 
> ax.add_patch(odd)
> ax.add_patch(even)
> 
> pad = 0.03
> width = 0.03
> 
> pos = ax2.get_position()
> 
> ax3 = fig.add_axes([pos.xmax + pad, pos.ymin, width, 0.7*(pos.ymax-pos.ymin) ])
> 
> plt.savefig('prova-vect-paper-test-2.eps', format='eps')
> 
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