[Ironpython-users] PyTest incompatible: Unsupported param dictionary type: IronPython.Runtime.PythonDictionary

Daniel Fernandez fernandez_dan2 at hotmail.com
Thu Jul 11 15:59:47 CEST 2013


I was able to reproduce this issue with this snippet of code. 
>>> from types import ModuleType>>> class A(ModuleType):...     def __init__(self, d):...         pass...>>> t = dict()>>> A(d = t)Traceback (most recent call last):  File "<stdin>", line 1, in <module>SystemError: Unsupported param dictionary type: IronPython.Runtime.PythonDictionary
I could only reproduce it when the class inherits from ModuleType. 
Danny
Date: Wed, 10 Jul 2013 21:17:55 -0700
From: slide.o.mix at gmail.com
To: timoteo1097 at gmail.com
CC: ironpython-users at python.org
Subject: Re: [Ironpython-users] PyTest incompatible: Unsupported param dictionary type: IronPython.Runtime.PythonDictionary

Can you show what line 33 in _apipkg.py is? 

On Wed, Jul 10, 2013 at 4:34 PM, Travis Lee <timoteo1097 at gmail.com> wrote:

I'm trying to use PyTest on IronPython. I haven't looked thoroughly but I've been told that PyTest does not use C extensions so it should theoretically work normally. 






c:\>"c:\Program Files (x86)\IronPython 2.7\ipy.exe"IronPython 2.7.3 (2.7.0.40) on .NET 4.0.30319.18047 (32-bit)




Type "help", "copyright", "credits" or "license" for more information.>>> import pytestTraceback (most recent call last):  File "<stdin>", line 1, in <module>




  File "C:\Users\***\AppData\Roaming\Python\IronPython27\site-packages\pytest-2.3.5-py2.7.egg\pytest.py", line 12, in <module>  File "C:\Users\***\AppData\Roaming\Python\IronPython27\site-packages\pytest-2.3.5-py2.7.egg\_pytest\core.py", line 7, in <module>




  File "C:\Program Files (x86)\IronPython 2.7\Lib\site-packages\py\__init__.py", line 19, in <module>  File "C:\Program Files (x86)\IronPython 2.7\Lib\site-packages\py\_apipkg.py", line 33, in initpkg




SystemError: Unsupported param dictionary type: IronPython.Runtime.PythonDictionary





I think it's expecting a standard Python dictionary. Is there any way around this?
Thanks.






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