[Python Glasgow] consecuetive members of a list

[Marc Cameron]

Hi Hedieh,

myList = [1,7,19,1110]
newList = []
for x in range(0, len(myList)-1):
    newStr = "(,)"
    newList.append("("+str(myList[x])+","+str(myList[x+1])+")")

Not sure if it meets your requirements, although this should work for all
intents and purposes. I am still relatively new to python so there may be a
better way.

Output = ['(1,7)', '(7,19)', '(19,1110)']

Cheers,

Marc C
------------------

Hi all,

Imagine I have a list like this:

myList= [1, 7, 19, 1110]

from this list I like to create a list of tuple of ranges like this.

[(1,7),(7,19),(19,1110)]

How can I do this in an efficient way ?

Thanks in advance.


On 30 April 2014 10:53, Hedieh Ebrahimi <hedieh.ebrahimi at amphos21.com>wrote:

> Hi all,
>
> Imagine I have a list like this:
>
> myList= [1, 7, 19, 1110]
>
> from this list I like to create a list of tuple of ranges like this.
>
> [(1,7),(7,19),(19,1110)]
>
> How can I do this in an efficient way ?
>
> Thanks in advance.
>
> _______________________________________________
> Glasgow mailing list
> Glasgow at python.org
> https://mail.python.org/mailman/listinfo/glasgow
>
>


-- 
Marc Cameron

*Contract Technical Artist and AR Generalist*
t: *+447595491710*
e: marccameron3D at gmail.com
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