[C++-sig] Wrapping a function that takes class type, such as type_info
Adam Preble
adam.preble at gmail.com
Sat Feb 25 15:25:13 CET 2012
It looks like PyObject_IsSubClass is working (!), but I wanted to follow up
on the boost::python::object stuff:
On Fri, Feb 24, 2012 at 9:56 PM, Jim Bosch <talljimbo at gmail.com> wrote:
> On 02/24/2012 02:31 AM, Adam Preble wrote:
>
>> Jim,
>>
>> I'll top post since I think this might get messy nice and fast
>> otherwise. I found I couldn't get to a method wrapped to type a
>> PyTypeObject* and only PyObject* would do.
>>
>
> Yeah, that's not surprising. You can also have it take a
> boost::python::object; that's essentially a smart pointer for PyObject*.
>
I couldn't get that to work. I can't pass it directly into
PyObject_IsSubclass, which isn't surprising. However, I couldn't do a get
or find anything else to extract the PyObject* out of it. Is there a trick
to this? I would wonder--is there a particular reason I should use that
instead? In my case, I'm not trying to sit on the pointer outside of the
class to Has(). The list I'm using has shared_ptr's of the underlying type
already. So I assume in my particular case I wouldn't have to worry about
it.
>
>
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