[C++-sig] Overriding operator= in boost python

[Stefan Seefeld]

Will Lee wrote:
> Hi,
> 
> Is there any way to wrap the operator= for a C++ assignment operator in
> boost python?  The documentation on operators doesn't seem to allow that (
> http://www.boost.org/libs/python/doc/v2/operators.html).  Essentially, I
> would like to do the python equalivalent of:
> 
> class A;
> 
> class B : public A;
> 
> I then have:
> 
> B& operator=(const A& a)
> {
> // assign A to B
> }
> 
> So that I can do (say bHolder is a class that contains a B instance):
> 
> a = A();
> bHolder.b = a;

The statement

c.b = a

in python will call c's '__setattr__' method, not, as in C++, c.b's
assignment operator. This is because the above changes the binding
of 'c.b', not the state of the object 'c.b' refers to.

Regards,
		Stefan

-- 

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