[C++-sig] How to wrap function pointer in python?

[David Abrahams]

Zhang Le <ejoy at peoplemail.com.cn> writes:

> Hi all,
>     I just want to wrap a C++ function which takes a C++ function
>     pointer as paramater. Then I think I can write callback function in python.
>
> In C++(part of source code):
> typedef boost::function<void (string s) > FUNC_TYPE;
>
> void foo(FUNC_TYPE fp)
> {
>     fp("hello,world!");
> }
>
> BOOST_PYTHON_MODULE(test)
> {
>     def("foo",foo) ;
> }
>
> In python I would like to write
> def hello(s):
>    print s 
> foo(hello)

What you're trying to do isn't possible, for Boost.Python or any other
wrapping system other than *possibly* something like weave which
recompiles C++ code on the fly during execution.  See
http://aspn.activestate.com/ASPN/Mail/Message/1554837 for more
details.

-- 
Dave Abrahams
Boost Consulting
www.boost-consulting.com