[Chicago] Question about accessing dictionary's elements.

[Lewit, Douglas]

I love it!  Thanks Jim.

On Sat, Sep 19, 2015 at 8:09 AM, Jimmy Calahorrano via Chicago <
chicago at python.org> wrote:

> is more elegant but not sure if is the best option:
>
>
> [A[key] for key in A.keys() if key[0] == 1]
>
>
>
> --------------------------------------------
> On Sat, 9/19/15, Lewit, Douglas <d-lewit at neiu.edu> wrote:
>
>  Subject: [Chicago] Question about accessing dictionary's elements.
>  To: "The Chicago Python Users Group" <chicago at python.org>
>  Date: Saturday, September 19, 2015, 7:43 AM
>
>  Hi
>  guys,
>  I have a problem and not
>  sure how to address it.  Let's say I have a simple
>  dictionary such as.
>  A = { (1, 2) : 10, (1, 3) :
>  15, (1, 4) : 50, (2, 0) : 2, (2, 5) : 8, (2, 12) : 19
>  }
>  I would like to access any
>  and all tuples whose first value is 1 or let's say 2.
>  How would I do that?
>  So what I'm trying to
>  go for is:
>  A[(1, placeholder for any
>  int value)] thus giving me all the values that correspond to
>  (1, #).  Not really sure how to go about this.  Unless....
>  I suppose I could do something like
>  this:
>  for key in
>  A:     if list(key)[0]
>  == 1:
>  print(A[key])  #### Or whatever I want to do with the
>  number.
>  Hmmm.... maybe that would
>  work, but is there a more "elegant" way to do
>  this?  Is there any "pattern matching" in Python
>  so that I could do this:
>  A[(1, #placeholder for any
>  int )]
>  Hey, thanks for your
>  help.
>  By the way, has anyone seen
>  the book LEARNING PYTHON by Mark Lutz?  Wow!  Full of
>  great information, but the book is HUGE!!!  I'll have
>  serious back problems if I carry that thing around in my
>  backpack!  There's something about small, lightweight
>  books that I really prefer.  (And then there's eBooks,
>  but that's a horse of a different color in my
>  opinion.)
>  Have a great weekend and
>  I'm looking forward to some ideas on the above
>  problem.  Thanks in advance.
>  Best,
>  Douglas
>  L.
>
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