[Chicago] sha1 of equal arrays different?

[T Wilson]

I'm still new to linux and learning fast.  The same goes for Python.  I'm
just getting my hands dirty with it.

On Tue, Oct 9, 2012 at 7:34 AM, Oren Livne <livne at uchicago.edu> wrote:

> With buffer() I get TypeError: single-segment buffer object expected
>
> Here's an isolated test case, does it fail on your machine too? (Try to
> rerun a few times)
>
> import unittest, numpy as np
> from numpy.ma.testutils import assert_equal
> from numpy import random
> from hashlib import sha1
>
> class TestHashable(unittest.**TestCase):
>     #-----------------------------**----------------
>     # Test Methods
>     #-----------------------------**----------------
>     def test_hashes_of_equal_objects_**from_slice_are_equal(self):
>         '''Test reproducability of hashing boolean rows of a matrix
> obtained from slicing.'''
>         #h = np.mod(np.arange(0, 100).reshape(100, 3), 2)
>         h = random.randint(0, 2, (4, 100, 2))
>         h = h[:, :, 1].transpose()
>         h = h[:, np.arange(0, 3)]
>         h = (h == 1)
>         print h
>         def get_index(h):
>             for j in range(1, h.shape[0]):
>                 if np.all(h[j] == h[0]):
>                     return j
>             return None
>         j = get_index(h)
>         assert_equal(h[0], h[j], 'Test objects should be equal, if not,
> rerun test')
>         def hash_array(x): return sha1(buffer(x.view(np.uint8)))**
> .hexdigest()
>         #def hash_array(x): x.tostring()
>         assert_equal(hash_array(h[0]), hash_array(h[j]), 'Hash should be
> reproducible')
>
> Thanks,
> Oren
>
>
> On 10/8/2012 10:44 PM, Kyle Cronan wrote:
>
>> I don't think I'm seeing that with my numpy here but maybe try passing
>> the view to buffer() before hashing?
>>
>> -Kyle
>>
>> On Mon, Oct 8, 2012 at 10:07 PM, Oren Livne <livne at uchicago.edu> wrote:
>>
>>> Dear All,
>>>
>>> I have a boolean numpy matrix whose rows 1 and 2 are equal. When I hash
>>> them
>>> using astype(uint8), I get equal digests, but different digests if
>>> view(uint8) is used. Why is that, or how can I interrogate the internals
>>> of
>>> the arrays to see why this happens? I rather use view(), because it's
>>> faster
>>> and requires no additional allocation. In IPython on top of Python 2.7.3.
>>>
>>> h[1]
>>> [ True False False False  True  True False  True  True True]
>>> h[2]
>>> [ True False False False  True  True False  True  True True]
>>> sha1(h[1].astype(uint8)).**hexdigest(), sha1(h[2].astype(uint8)).**
>>> hexdigest()
>>> ('**bc4ec9b78ad53ce78ae24643d8ff30**2a9ae03bd0',
>>> '**bc4ec9b78ad53ce78ae24643d8ff30**2a9ae03bd0')
>>> sha1(h[1].view(uint8)).**hexdigest(), sha1(h[2].view(uint8)).**
>>> hexdigest()
>>> ('**887ed6519d5b521fe5181f9329b98c**65897a6a47',
>>> '**d8cb41ec47d6e01c25986bbd605d39**e777e5b4f7')
>>>
>>> Thank you so much,
>>> Oren
>>>
>>> --
>>> A person is just about as big as the things that make him angry.
>>>
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>
>
> --
> A person is just about as big as the things that make him angry.
>
> ______________________________**_________________
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