[Chicago] order of keyword arguments

[Igor Sylvester]

Hi Everyone,

Is there a way to obtain the order of keyword arguments in this example:

def foo(**kargs):
            print kargs.items()

The call foo(A=0, B=1) could print (('A', 0), ('B', 1)) or (('B', 1), ('A',
0)).

Since dictionaries do not know about ordering, I can't obtain the order of
keyword arguments by simply looking into kargs.
Perhaps there is a way to introspect the function stack to get a hold of the
order of the arguments.  Does anyone know if this is possible?

Thanks!
Igor
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