[Baypiggies] mmap question

[K. Richard Pixley]

It's like magic!  I post... and immediately the answer comes to me.  *sigh*

xmap.find(ymap)

Thanks for, um, being here for me.  :).

--rich

On 20101217 21:54, K. Richard Pixley wrote:
> Ok, I'm stumped.
>
> I have two files.  They are the same size and I've mmaped them both 
> into xmap and ymap.  I'd like to compare their contents but without 
> copying them into yet another chunk of memory before I do so.  There 
> should be a way to bitblt these things.
>
> The only things I can think to do involve forcing a string copy first.
>
>     xmap[:] == ymap[:]
>     bytearray(xmap) == bytearray(ymap)
>     xmap.read() == ymap.read()
>
> Can anyone think of a way to do this without first copying them to 
> strings?
>
> --rich
>
>
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