[Baypiggies] a python puzzle
Emile van Sebille
emile at fenx.com
Wed Apr 14 18:03:40 CEST 2010
a = [1, 1, 2, 4, 6, 8, 9]
b = [1, 3, 4, 5, 6, 7, 8]
def popwhile(l,t):
r = []
while l[:1] == t:
r.append(l.pop(0))
return r
while bool(a or b):
m = min(a[:1],b[:1]) or max(a[:1],b[:1])
print popwhile(a,m), popwhile(b,m)
Emile
On 4/14/2010 8:20 AM Brent Pedersen said...
> hi, in trying to write a func that does a kind of merging of 2 sorted lists,
> i've come up with a fairly simple implementation that "almost works":
> http://gist.github.com/365485
>
> but it hits StopIteration before returning the last value ([9], None)
> i can wrap the whole thing in a bunch more if statements, i've tried
> heapq.merge, but cant find a nice solution.
>
> any ideas? i think it's an interesting problem.
> -brent
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