[BangPypers] parsing xml

[Sidu Ponnappa]

If you're doing this repeatedly, you may want to just delegate to a
native XPath implementation. I haven't done much Python, so I can't
comment on your choices, but in Ruby I'd simply hand off to libXML
using Nokogiri. This approach should be a whole lot faster, but I'd
advise benchmarking first because, as I said, I know little about
Python.

Best,
Sidu.
http://sidu.in

On Thu, Jul 28, 2011 at 4:01 PM, Kenneth Gonsalves <lawgon at gmail.com> wrote:
> On Thu, 2011-07-28 at 15:33 +0530, Anand Chitipothu wrote:
>> > I want to get the value of the distance element - 1489. What is the
>> > simplest way of doing this?
>>
>> >>> from xml.dom import minidom
>> >>> dom = minidom.parseString(x)
>> >>> dom.getElementsByTagName("distance")[0].childNodes[0].nodeValue
>> u'1489'
>
> thanks - perfect.
> --
> regards
> Kenneth Gonsalves
>
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