[BangPypers] One python question (from verilog)
Deepak Patel
patel.deepak.09 at gmail.com
Sat Sep 20 04:02:36 CEST 2008
Pradeep,
Thanks.
I am not aware if Python provides the feature of accessing the value by its
bit poition:
Can we do "if read_data[bit_pos] === poll_val:" in Python? Can you please
let me know little bit more about this line?
Whether Read_data will be declread as list() or dict()?
Thanks,
Deepak
On Fri, Sep 19, 2008 at 5:44 PM, Pradeep Gowda <pradeep at btbytes.com> wrote:
> The syntax looks familiar, almost python like.
> The equivalent python code would be*:
>
> def poll_reg(bit_pos, poll_val, reg_offset):
> matched = 0
> while matched != 1:
> read_data = read_reg(reg_offset)
> if read_data[bit_pos] === poll_val:
> matched = 1
> else:
> matched = 0
> return matched
>
> * Implementing read_reg is left as an exercise to the developer :p
>
> I'm not aware of any python library methods which allow one to access
> registers. But, the read_reg() can be implmented in C and
> imported into Python.
>
> Any low level operation like register access is usually delegated to .
>
> HTH,
> PG
>
>
> On Sep 19, 2008, at 7:02 PM, Deepak Patel wrote:
>
> Hello all,
>>
>> I want to a write a method in Python to poll a register for '1' or '0'. It
>> is kind of very simple in verilog, but not sure if python provides
>> flexibility or not.
>>
>> My algorithm (kind of Verilog syntax where I can access the bits without
>> any extra processing) is as follows:
>>
>> poll_reg ( input bit_pos, input poll_val, reg_offset)
>> {
>> // In this bit_pos is the position of bit in my register read which are
>> being polled to become poll_val. Poll_val can be either 0 or 1.
>>
>> matched = 0;
>> while (matched != 1)
>> begin
>> read_data = read_reg(reg_offset);
>> if (read_data[bit_pos] == poll_val)
>> begin
>> matched = 1;
>> end
>> else
>> begin
>> matched = 0;
>> end
>> end
>> }
>>
>> Is there a way to do above in Python?
>> Thanks,
>> Deepak
>>
>>
>>
>>
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>>
>
> Pradeep Kishore Gowda
> http://pradeepgowda.com
> pradeep at btbytes.com
> +1-317-564-4660 (Day Phone)
>
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>
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