[XML-SIG] Re: Could somebody help me?

[Prasad PS]

Sure, here is the code

In the code below, what I am doing is - I am opening an xml file and
appending a node to the root document. Then I add this root document to
the xml file
fp = open (string.strip(self.cnfDtls.GetLogFilePath()), 'w')
xml.dom.ext.PrettyPrint(doc, self.xmlFile)
self.xmlFile.write("\n") 
fp.close().

So for each appending of node, the file is opened and the new root
document with the appeneded node is re-written to the file. This is
taking lot of time. 
Is there any way to append a node to the xml file without re-writing the
file?


Prasad.p.s.

                        fp = open(
string.strip(self.cnfDtls.GetLogFilePath()), 'r')
            doc = FromXmlStream(fp)
##        else:
##            print "File not available"
##        print "The Doc is ", doc
####        self.testcases.appendChild(doc.createTextNode("\n  "))
##        print
**************************************************************", doc
        top_nodeList = doc.getElementsByTagName("Logger")
##        print "Hi", top_nodeList
        tc = doc.createElement("LogDetails")
##        top_nodeList[0].appendChild(tc)
        tc.appendChild(doc.createTextNode("\n   "))
        i=0
        for elements in self.firstPart:
          ln = doc.createElement(elements)
          if elements == "Steps":
              stepParts = self.parts[i]
##              print "The Step Part is ", stepParts
              for index in range(len(stepParts)):
                  step = stepParts[index]
                  msgSent = step[0]
                  msgRecd = step[1]
                  timeout = step[2]
                  stateMsg = step[3]
                  stepNode = doc.createElement("Step")
                  mvalueNode1 = doc.createElement("MessageSent")
                  for msgIndex in range(len(msgSent)):
                      ##
stepNode.appendChild(mvalueNode1)
                      keyL = msgSent[msgIndex].keys()
                      for m in range(len(keyL)):
                          keyNode1 = doc.createElement(keyL[m])
                          valL = msgSent[msgIndex][keyL[m]]
                          if type(valL) == str:
                              
##                              attNode0 = doc.createElement()
 
keyNode1.appendChild(doc.createTextNode(valL))       
##                              mvalueNode1.appendChild(keyNode1)
                          else:
                              keysL = valL.keys()
                              for n in range(len(keysL)):
                                  attNode1 = doc.createElement(keysL[n])
 
attNode1.appendChild(doc.createTextNode(valL[keysL[n]]))
                                  keyNode1.appendChild(attNode1)
                        
                          mvalueNode1.appendChild(keyNode1)
                  stepNode.appendChild(mvalueNode1)
                  
                  mvalueNode2 = doc.createElement("MessageReceived")
                  for msgIndex in range(len(msgRecd)):
                      keyL = msgRecd[msgIndex].keys()
                      for m in range(len(keyL)):
                          keyNode2 = doc.createElement(keyL[m])
                          valL2 = msgRecd[msgIndex][keyL[m]]
                          if type(valL2) == str:
 
keyNode2.appendChild(doc.createTextNode(valL2))       
##                              mvalueNode2.appendChild(keyNode1)
                          else:
                              keysL = valL2.keys()
                              for n in range(len(keysL)):
                                  attNode2 = doc.createElement(keysL[n])
 
attNode2.appendChild(doc.createTextNode(valL2[keysL[n]]))
                                  keyNode2.appendChild(attNode2)
                          mvalueNode2.appendChild(keyNode2)
                  stepNode.appendChild(mvalueNode2)
                  timeoutNode = doc.createElement("TimeOut")
                  timeoutNode.appendChild(doc.createTextNode(timeout))
                  stepNode.appendChild(timeoutNode)
                  stateMsgNode = doc.createElement("StateMessage")
                  stateMsgNode.appendChild(doc.createTextNode(stateMsg))
                  stepNode.appendChild(stateMsgNode)
                  ln.appendChild(stepNode)
          else:
              ln.appendChild(doc.createTextNode(self.parts[i]))
          tc.appendChild(ln)
          tc.appendChild(doc.createTextNode("\n  "))
          i = i+1
        t = doc.createTextNode("\n")
        top_nodeList[0].appendChild(tc)
        top_nodeList[0].appendChild(t)
        fp.close()

        fp = open (string.strip(self.cnfDtls.GetLogFilePath()), 'w')
        xml.dom.ext.PrettyPrint(doc, self.xmlFile)
        self.xmlFile.write("\n") 
        fp.close()



-----Original Message-----
From: xml-sig-bounces at python.org [mailto:xml-sig-bounces at python.org] On
Behalf Of Fredrik Lundh
Sent: Friday, January 28, 2005 3:34 PM
To: xml-sig at python.org
Subject: [XML-SIG] Re: Could somebody help me?

Prasad PS wrote:

> I too have followed the second choice but what happened was, when I
add
> the root document to the xml file, I find the previous content and the
< combination of the previous and the new content in the file and
moreover
> xml declarator is appearing twice.

can you perhaps post a short snippet that illustrates the problem?

is using a traditional DOM API an absolute requirement, btw?

</F> 



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